(3 points) The altitude of a triangle is increasing at a rate of 1 cm/min<span> while the area of the triangle is increasing at a rate of 20 cm2/min. At what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100 cm2. = 2, namely, the base of the triangle is increasing at a rate of </span>2 cm/min<span>.</span>
I think you meant "y = 4 arccot (x)."
This is equivalent to:
y
---- = arccot x
4
and so cot (y/4) = x
Answer:
The answer is C
Step-by-step explanation:
121/2 = 720/p
720*2= 121p
1440=121p
divide by 121
=12%
Area of a circle = (3.14) * r^2
d = 7
r = 3.5
a = (3.14) * 3.5^2
a = (3.14) * 12.25
a = 38.47
