The moles of ammonium nitrate needed to dissolve 0.35 moles
The moles of water that will react is 0.35 moles as due to ratio
so mass of water will be 0.35 x 18=6.3g
MASS OF WATER WILL BE 6.3 g
I’m not totally sure but I think the answer is B
The number of moles hydrogen produced when 6 moles of sodium are used is calculated as below
2Na + 2H2O = 2NaOH +H2
by use of mole ratio between Na to H2 which is 2:1 the moles of H2 is therefore
= 6 x1/2 = 3 moles of H2
4.01 kg in grams :
4.01 x 1000 = 4010 g
Density = mass / volume
7.86 = 4010 / volume
Volume = 4010 / 7.86
Volume = 510.17 cm³
hope this helps!
