Solute is substance which is dissolve in a solvent and Solvent is a substance that dissolves solute in a solution.
Aluminum hydroxide 
can behave as a base and neutralize sulfuric acid 
as in the following equation:
(Balanced)
(a)
. Thus the ratio between the number of moles of the two reactants available:
![n(\text{Al}(\text{OH})_3, \text{supplied}) / n(\text{H}_2\text{SO}_4, \text{supplied})\\= [m(\text{Al}(\text{OH})_3)/ M(\text{Al}(\text{OH})_3)] / [n(\text{H}_2\text{SO}_4) / M(\text{H}_2\text{SO}_4)]\\= [23.7 / (26.98 + 3 \times(16.00 + 1.008))]/[29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00)]\\\approx 1.01](https://tex.z-dn.net/?f=n%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%2C%20%5Ctext%7Bsupplied%7D%29%20%2F%20n%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%2C%20%5Ctext%7Bsupplied%7D%29%5C%5C%3D%20%5Bm%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%29%2F%20M%28%5Ctext%7BAl%7D%28%5Ctext%7BOH%7D%29_3%29%5D%20%2F%20%5Bn%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%29%20%2F%20M%28%5Ctext%7BH%7D_2%5Ctext%7BSO%7D_4%29%5D%5C%5C%3D%20%5B23.7%20%2F%20%2826.98%20%2B%203%20%5Ctimes%2816.00%20%2B%201.008%29%29%5D%2F%5B29.5%20%2F%20%282%20%5Ctimes%201.008%20%2B%2032.07%20%2B%204%20%5Ctimes%2016.00%29%5D%5C%5C%5Capprox%201.01)
The value of this ratio required to lead to a complete reaction is derived from coefficients found in the balanced equation:
The ratio for the complete reaction is smaller than that of the reactants available, indicating that the species represented on the numerator, , is in excess while the one on the denominator, , serves as the limiting reagent.
(b)
The quantity of water produced is dependent on the amount of limiting reactants available. 
of sulfuric acid is supplied in this reaction as the limiting reagent. 
moles of water molecules are produced for every 
moles of sulfuric acid consumed. The reaction would thus give rise to 
of water molecules, which have a mass of 
.
(c)
(d)
The quantity of , the reactant in excess, is dependent on the number of moles of this species consumed in the reaction and thus the quantity of the limiting reagent available. The consumption of every moles of sulfuric acid, the limiting reagent, removes 
moles of aluminum hydroxide from the solution. 
of sulfuric acid is initially available as previously stated such that 
, or 
, of would be eventually consumed.
of would thus be in excess by the end of the reaction process.
Answer:
0.01932 L
Explanation:
First we <u>convert 105 mM to M</u>:
Next we <u>convert 552 mL to L</u>:
Then we use the following equation:
Where:
We<u> input the given data</u>:
- 3 M * V₁ = 0.105 M * 0.552 L
And <u>solve for V₁</u>:
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Molar mass of 13c = 13 grams
number of moles = mass / molar mass
therefore,
number of moles = 7 / 13
To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:
number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms
