Since the pentagon is regular, the sides are all of equal length. This tells you
... 5x-27 = 2x-6
... 3x = 21 . . . . . . . add 27-2x
... x = 7
The length of a side can be found by subtituting this value into either expression.
... 2·7-6 = 8 . . . . inches
Let's call the smaller side
. This means that the other side of the rectangle is
.
In this problem, we are trying to find the lengths of the sides. The problem gives us someinformation about the sides, but that's really it. However, the problem also let's us know that the diagonal of the rectangle (the line connecting opposite corners of the rectangle) is 34 cm long.
This fact is very important, because we can actually make a triangle, with the smaller side, bigger side, and the diagonal of the rectangle. Additionally, since we are working with rectangles, we know that the sides form a right angle. Since we are constructing a triangle with the sides as the legs, we know that we are going to be constructing a right triangle, which means that we can work with Pythagorean's Theorem.
Remember that Pythaogrean's Theorem is:

and
are the lengths of the legs of the triangle
is the length of the hypotenuse
Applying the Pythagorean Theorem to this problem, we get:

Let's simplify and solve for
:


- Simplify left hand side and evalutate


- Subtract 1156 from both sides of the equation and combine like terms


- Apply the Zero Product Property to solve for


is an extraneous solution because you can't have a negative side length
We have now found that the smaller side is 16 cm long. Since the larger side is 14 cm longer, it can be found as shown:

The sides are length 16 cm and 30 cm.
Answer:
I think 1.5-2
Step-by-step explanation:
keep it up
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%