Choose the statement that is true. WILL MARK BRAINLIEST

Mathematics

1 answer:

Margarita [4]2 years ago

5 0

Answer:

option A is correct

hope it helps :)

Step-by-step explanation:

The Standard Deviation Rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean. It states that

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

Therefore, looking at the options, the true statement id

A) For a normal distribution, 99.7% of the distribution is within 3 standard deviations.

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Which expression is equivalent to ( 4 1/3)^3 ?

shutvik [7]

(13/3)^3 or (13/3)•(13/3)•(13/3)

5 0

2 years ago

If one person recruits five people and each recruited person recruits 5 more, and so on, 15 cycles; how many people would that b

jek_recluse [69]

Answer:

y=5^x

5^15= 30517578125 people

Step-by-step explanation:

x=# of cycles= 15 cycles

y= #of people recruited = what we're figuring out

Plug in 15 for x in the equation y=5^x

y= 5^15= 30517578125 people

3 0

3 years ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$