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Vladimir [108]
2 years ago
6

Which must be true of a quadratic function whose vertex is the same as its y-intercept?

Mathematics
1 answer:
BaLLatris [955]2 years ago
7 0

Answer:  Choice A

The axis of symmetry for the function is x = 0.

===========================================================

Explanation:

The vertex is on the axis of symmetry. Since the vertex is on the y axis, this means the y axis itself is the axis of symmetry. The y axis is represented by the equation x = 0. Every point on the y axis has an x coordinate of 0. Example points are (0,2) and (0,5).

This parabola may have 0 roots, 1 root, or 2 roots.

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Solve for x: 4(3 - 2x) = 2(10 - 8x) Type only your solution, do not type x = *
velikii [3]
The solution is x = 1
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3 years ago
I just two questions :)
pogonyaev

Answer:

Hi There!!

Step-by-step explanation:

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<h2>1. C</h2><h2>2. A</h2><h2 /><h2 />

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7 0
3 years ago
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Advocard [28]

Answer:

negative multiples of 3 less than -3

Step-by-step explanation:

if m <9, then

m ={8,7,6,5,4,3,2,1,0,-1,-2,....,..........}

And |6m-55|

So is said that,

when, m= 8

6(8)-55=-6

when, m=7

6(7)-54=-12

when, m = 6

6(6)-54=-18

Since the trend is negative multiples of 3 less than -3

this is my answer

8 0
3 years ago
If f(x) -V7-3, complete the following statement (round your answer
nikklg [1K]

Answer:

- 1.67

Step-by-step explanation:

f(x) = \frac{3}{7+2} - \sqrt{7-3}

    =  \frac{3}{9} - \sqrt{4}

    = \frac{1}{3} - 2

    = - 1 \frac{2}{3}

    = -1.6666666

    = -1.67

5 0
3 years ago
given y&gt;0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
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