Answer:
6.3m/s
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Height = 2m
Unknown:
Velocity when the ball hits the ground = ?
Solution:
Since the potential energy is transformed into kinetic energy;
P.E = K.E
mgh =
m v²
cancelling m;
gh =
v²
v² = 2gh
v = √2gh
Insert the parameters and solve;
v = √2gh = √ 2 x 9.8 x 2 = 6.3m/s
The car is moving faster/accelerating quicker
Answer:
A circuit that has little or no resistance
Explanation:
Apex
Answer:
10N
Explanation:
Equation: ΣF = ma
Fapp = ma
Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)
Fapp = 10*kg*m/s^2
Fapp = 10N
You sure wouldn't want something like cm/s or (yikes cm/hr). You want a reasonable number for sports usually between 0 and 100
Km / hour would be a good choice.
The next town to where I live is 25 km away. On a good day, I can make it there in about 3/4 of an hour.
Speed = 25 km / 0.75 hour = 33.3 km/hour. That's actually a little fast most of the time. But you should understand what I mean.