Answer:
The correct answer is "6666.67 N".
Explanation:
The given values are:
Mass,
m = 0.100
Relative speed,
v = 4.00 x 10³
time,
t = 6.00 x 10⁻⁸
As we know,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
Explanation:
If the center of the load is directly above the vertebrae, there is no torque in the system. This is a good thing so that the vertebrae are not put out of alignment over time. (Of course, this still doesn't prevent compression of the vertebrae over time, which is a possibility.)
Answer:
Distance will decrease and work will decrease:
F = m a Newton's Second Law
a = F / m decreasing force will decrease acceleration
S = 1/2 a t^2 = 1/2 (F / m) t^2 distance traveled will decrease as force decreases
W = F * S work will decrease as both force and distance decrease