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gavmur [86]
3 years ago
11

Which of the following changes will always increase the efficiency of a thermodynamic engine? Choose all correct statements.

Physics
2 answers:
slava [35]3 years ago
6 0

Answer:

option (c)

Explanation:

The efficiency of the engine is given by

\eta =1-\frac{T_{c}}{T_{H}}

to increase the efficiency of the engine, the temperature of the cold reservoir should be decreased and thus the temperature of hot reservoir be increased.

So, decrease the ratio of Tc/TH.

option (C)

Ilya [14]3 years ago
5 0

Answer:B,C,D

Explanation:

Thermodynamic  efficiency is given by

\eta =1-\frac{T_C}{T-H}

\eta efficiency can be increased by Keeping _c constant and increasing T_H

Keeping T_H constant and decreasing T_c

by increasing \Delta T=T_H-T_c

by decreasing \frac{T_C}{T_H} ratio          

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The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

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