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3 years ago

Which statement is true for any electrochemical cell?

1 answer:

Nadusha1986 [10]3 years ago

7 0

The answer is (1) oxidation occurs at the anode, only. And reduction occurs at the cathode, only. The difference between voltaic cell and electrolytic cell is the flow direction of energy(electric to chemical or chemical to electric).

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The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

5 0

3 years ago

which of the following describes a similarity between a liquid and gas A. both are forms of heat are used to warm objects. C. bo

Leona [35]

Answer:

It's A

Explanation:

Liquid can heat things and so can steam.

8 0

3 years ago

On the first day of school, a class of th-grade students are given tour identical cubes of hard clay. The cubes are placed in fo

matrenka [14]

Answer:

sample 4

Explanation:

6 0

3 years ago

Please Help ASAP........................

Gennadij [26K]

C. Wavelength will increase

6 0

3 years ago

Can someone please help me on the second one? I have no idea what to do.

Aleks [24]

The reaction will produce 12.1 g Ag₂S.

Balanced equation = 2Ag + S ⟶ Ag₂S

Mass of Ag₂S = 10.5 g Ag × (1 mol Ag/107.87 g Ag) × (1 mol Ag₂S/2 mol Ag)

× (247.80 g Ag₂S/1 mol Ag₂S) = 12.1 g Ag₂S

8 0

4 years ago