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3 years ago

How many carbon atoms are represented by the model below?

Chemistry

2 answers:

Elis [28]3 years ago

5 0

Answer:

Explanation:

Mama L [17]3 years ago

4 0

In the model it shows 3 carbon atoms, the person above me is correct

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A typical aspirin tablet contains 500. mg of c9h8o4. how many moles of c9h8o4 molecules and how many molecules of acetylsalicyli

joja [24]

From the periodic table:
molar mass of carbon = 12 gm
molar mass of hydrogen = 1 gm
molar mass of oxygen = 16 gm

molar mass of acetylsalicylic acid = 9(12) + 8(1) + 4(16) = 180 gm

Number of moles = mass / molar mass = 0.5 / 180 = 2.778 x 10^-3 moles

To get the number of molecules, we multiply the number of moles by Avogadro's number as follows:
number of molecules = 2.778x10^-3x6.02x10^23 =1.672 x 10^21 molecules

6 0

3 years ago

Identify the group or period that matches each description.

Mekhanik [1.2K]

Answer:

a.6th period

b.groupIIA

3 0

2 years ago

EXTRA CREDIT

marin [14]

Answer:

$\huge\boxed{\sf 36\ H\ atoms}$

Explanation:

Molecular formula from Glucose:

C₆H₁₂O₆

3 moles of Glucose:

3C₆H₁₂O₆

In 1 mole of Glucose, there are 12 hydrogen atoms.

In 3 moles:

= 12 × 3

= 36 H atoms

$\rule[225]{225}{2}$

5 0

2 years ago

Solve fasttt C7H17+O2=CO2+H2O Balancing Equations

sertanlavr [38]

Answer:

The answer to your question is

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Explanation:

Write the equation

C₇H₁₇ + O₂ ⇒ CO₂ + H₂O

Process

1.- Check if the equation is balanced

Reactants Element Products

7 C 1

17 H 2

2 O 3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O

C₇H₁₇ + O₂ ⇒ 7CO₂ + $\frac{17}{2}$ H₂O

Reactants Element Products

7 C 7

17 H 17

2 O 51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Reactants Element Products

28 C 28

68 H 68

90 O 90

5 0

3 years ago

A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat

loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

Volume of the solution = 1 lit = 1000 ml

Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

Mass percentage of H2SO4 (%w/w) is 42.99 %

3 0

3 years ago