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Lubov Fominskaja [6]
3 years ago
11

How many moles are in 454 grams of dinitrogen trioxide (N2O3) ?

Chemistry
1 answer:
balu736 [363]3 years ago
6 0

Answer:

5.97 mol

Explanation:

To find the number of moles when given the mass of a substance, we divide the mass of the sample by its molar mass.

so, we get,

nN203 = 454 g / 76.01 g /mol

= 5.97 mol

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The balanced nuclear equation for the reaction is

<h3>²³⁵₉₂U + ¹₀n —> ¹⁵⁵₆₂Sm +  ⁷⁸₃₀Zn + 3(¹₀n)</h3>

From the question given above, we were told that:

<u>A fast-moving neutron strikes a ²³⁵U nucleus. The nucleus shatters producing ¹⁵⁵Sm, ⁷⁸Zn, and three neutrons.</u>

The nuclear equation can be written as follow:

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Uranium + neutron —> Samarium + Zinc + 3 moles of neutron

<h3>²³⁵₉₂U + ¹₀n —> ¹⁵⁵₆₂Sm +  ⁷⁸₃₀Zn + 3(¹₀n)</h3>

 

 The nuclear equation above is balanced.

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