If the echo is detected 2 seconds after the ping is transmitted,
then the sound has traveled
(2 sec) x (1533 meter/sec) = 3,066 meters.
But the sound had to travel down from the boat to the bottom, then
get reflected, then travel up from the bottom to the boat. So the
sound actually traveled a distance equal to double the depth.
The depth is (1/2) (3,066 meters) = 1,533 meters .
(about 5,030 feet)
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
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<em>Additional comment</em>
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
Answer:
The speed of sound is 366.67 m/s.
Explanation:
height, h = 44 m
total time, T = 3.12 s
Let the time taken by the stone to hit the water is t.
use second equation of motion
Time taken by sound to g up
t'=T - t = 3.12- 3 = 0.12 s
The speed of sound is