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insens350 [35]
3 years ago
15

Which of the following are likely to form a covalent bond?

Physics
2 answers:
sesenic [268]3 years ago
8 0
The answer is
"C"
<span>Magnesium and chlorine</span>
Vera_Pavlovna [14]3 years ago
4 0

its c- sulfur and oxygen trust me

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How can a volcano develop in the middle of a tectonic plate?
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Answer:

Volcanoes that form away from plate boundaries are created by hotspots. A hotspot is an area in the mantle that is believed to be somewhat hotter than the surrounding material. The rising magma from the hotspot can push its way through the crust and burst out at the surface, forming a volcano.

Explanation:

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How could you compare the energy carried in two different longitudinal waves
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A rocket has a mass 280(103) slugs on earth. Specify its mass in SI units, and its weight in SI units.
saw5 [17]

To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then

A: Using the conversion ratio of slug to kilogram we have to,

1 slug = 14.59kg

Then

m = 280*10^3 slugs (\frac{14.59kg}{1slug})

m = 4.09*10^6kg

B: Using Newton's second law we have to,

W = mg

W = (4.09*10^6)(9.8)

W = 40034960N\approx 4*10^7N

8 0
3 years ago
How is an elliptical galaxy different from a spiral galaxy?
laiz [17]
An elliptical galaxy is a type of galaxy having an approximately ellipsoidal shape and a smooth, nearly featureless brightness profile.

Unlike flat spiral galaxies with organization and structure, they are more three-dimensional, without much structure, and their stars are in somewhat random orbits around the center.
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3 years ago
A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction
Nezavi [6.7K]

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

F_{n} = Normal force on the block by the ramp

f_{k} = kinetic frictional force

Force equation perpendicular to ramp surface is given as

F_{n} = mg Cos65

Kinetic frictional force is given as

f_{k} = \mu F_{n}

f_{k} = \mu mg Cos65

Force equation parallel to ramp surface is given as

mg Sin65 - f_{k} = ma

mg Sin65 - \mu mg Cos65 = ma

g Sin65 - \mu g Cos65 = a

(9.8) Sin65 - (0.17) (9.8) Cos65 = a

a = 8.2 m/s²

4 0
4 years ago
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