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Anastaziya [24]
3 years ago
9

What happens when a roller coaster car moves down from the top of a hill?

Physics
2 answers:
Andrew [12]3 years ago
5 0

Answer:

Gravitational potential energy is converted into kinetic energy

Explanation:

At the top of the hill, the roller coaster car has gravitational potential energy, which is given by:

U=mgh

where m is the mass of the car, g is the gravitational acceleration, h is the height of the hill.

As the car descends the hill, it gains speed (v), so it also gains kinetic energy, given by:

K=\frac{1}{2}mv^2

where v is the speed of the car.

The mechanical energy of the car is the sum of its potential energy and kinetic energy:

E=U+K

In absence of friction, the law of conservation of energy states that the mechanical energy of the car is constant. Therefore, since as the car moves down the hill the potential energy decreases (because the height, h, decreases), it means that the kinetic energy must increase (and this is wy the speed increases). So we can say that gravitational potential energy is converted into kinetic energy.

VLD [36.1K]3 years ago
3 0
When the roller coaster moves down from the top of the hill, all of its stored potential energy is converted into kinetic energy to move it and when it goes back up the hill it turns kinetic into potential.

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A heating curve is a graph that shows the temperature change of a substance as
harkovskaia [24]

Answer:

This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.

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2 years ago
A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the
Vesna [10]

So, based on the angle values that have been found, the angle of elevation of the nozzle can be <u>16° or 74°</u>.

<h3>Introduction</h3>

Hi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :

\boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}}

With the following condition :

  • \sf{x_{max}} = the farthest distance of the parabolic movement (m)
  • \sf{v_0} = initial speed (m/s)
  • \sf{\theta} = elevation angle (°)
  • g = acceleration due to gravity (m/s²)

<h3>Problem Solving :</h3>

We know that :

  • \sf{x_{max}} = the farthest distance of the parabolic movement = 2.5 m
  • \sf{v_0} = initial speed = 6.8 m/s
  • g = acceleration due to gravity = 9.8 m/s²
<h3>What was asked :</h3>
  • \sf{\theta} = elevation angle = ... °

Step by Step :

  • Find the equation value \sf{\bold{theta}} (elevation angle)

\sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}

\sf{x_{max}  \cdot g = (v_0)^2 \cdot \sin(2 \theta)}

\sf{\frac{x_{max}  \cdot g}{(v_0)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =   \sin(2 \theta)}

\sf{\frac{2.5  \cdot 9.8}{(6.8)^2} =  \sin(2 \theta)}

\sf{\frac{24.5}{46.24} = \sin(2 \theta)}

\sf{\sin(2 \theta) \approx 0.53}

\sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)}

  • Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.

First Probability

\sf{2 \theta = 32^o + k \cdot 360^o}

\sf{\theta = 16^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 16^o + 0 = 16^o} (T)

→ \sf{k = 1 \rightarrow 16^o + 180^o = 196^o} (F)

Second Probability

\sf{2 \theta = (180^o - 32^o) + k \cdot 360^o}

\sf{2 \theta = 148^o + k \cdot 360^o}

\sf{\theta = 74^o + k \cdot 180^o}

→ \sf{k = 0 \rightarrow 74^o + 0 = 74^o} (T)

→ \sf{k = 1 \rightarrow 74^o + 180^o = 254^o} (F)

\boxed{\sf{\therefore \theta \{16^o , 74^o\} }}

<h3>Conclusion</h3>

So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.

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What is frictional force?<br>how to Express frictional force?
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Answer:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.

Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

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The answer is C. strict
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What derived unit is used to measure the slope of the line in this graph?
vlabodo [156]

Answer:

C. g/cm³

Explanation:

The slope is measured by calculating the variation of the Y values over the X values between two points on a line.  

So, the formula is: Slope = Δy/Δx

That means that we also take the units.

In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.

Dividing a Y-variation over an X-variation will give you g/cm³.

In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)

So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³

3 0
4 years ago
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