Answer:
6 % is the answer
Step-by-step explanation:
6.50 x 6%=0.39
6.50+0.39=6.89
Answer: 63lbs
Step-by-step explanation:
The truck can only hold 16crates and each crate weigh 12lbs, the total weight of the 16 crates will be 12×16= 192lbs
This shows that the truck can only contain extra load of 1200lbs - 192lbs = 1008lbs (excluding weight of crates).
To get the shipment weigh close to the total of 1200lbs, the truck must be loaded with engine components not more than 1008lbs.
Since we have 16 crates to fill with engine components not more than 1008lb, each crates will therefore must not exceed 1008/16 pounds of engine components which is equivalent to 63lbs.
Therefore, the manager should instruct the workers to put 63lbs of machine components in "each crate" in order to get the shipment weight as close as possible to 1200 lbs.
If the right hand side of a quadratic equation does not equal zero, you need to subtract the number...
Answer:
Step-by-step example explanation:
DOMAIN:
{
x
∣
x
≠
3
2
}
RANGE:
{
y
∣
y
≠
3
2
}
Explanation:
The domain consists of all numbers you can legally plug into the original. The excluded "illegal" values would be dividing by zero or negatives under square roots.
This expression has a denominator, so there is a risk of illegally dividing by zero. This would happen only if
2
x
−
3
=
0
2
x
=
3
x
=
3
2
This means that
x
=
3
/
2
is excluded from the domain. Therefore,
Domain: All real numbers except
x
=
3
/
2
. More formally, you could state the domain as
{
x
∣
x
≠
3
2
}
.
For rational functions, you find the range by evaluating the degree of the numerator compared to the degree of the denominator. If the degree of the top > degree of bottoms, then you have a horizontal asymptote at
y
=
0
. If they are equal, you have a horizontal asymptote. The coefficient of highest degree in the numerator is divided by the coefficient of the highest degree on the bottom. The result is
y
=
that fraction. So in our case, you have a horizontal asymptote at
y
=
3
2
<span> Plot the points and draw the triangle. Now you have to draw a line that passes through a point, perpendicular to the triangle side that it's opposite from. Then do that again with a second point. The intersection of these two points will give you the Orthocenter. (You don't need to do it for the third point; it will pass through it anyway, but you only need two intersecting lines to define a point!) Since AB is a horizontal line, it will probably be easiest to start with the line perpendicular to AB that passes through C. You'll find that this is just the vertical line x=1. Now just pick another point and do it again. (Hint: if you know two points, you can find their slope, and you know that lines perpendicular to each other have negative reciprocal slopes.)</span>
