Hi there!
Our interval is from 0 to 3, with 6 intervals. Thus:
3 ÷ 6 = 0.5, which is our width for each rectangle.
Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:
0.5, 1, 1.5, 2, 2.5, 3
Evaluate:
(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =
Simplify:
0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875
If B is the midpoint of AC, then AB=BC. It is also BC=AC-AB
AB = x + 6
AC = 5x - 6
BC = (5x - 6) - (x + 6)
We can kinda use distributive property, like this:
BC = 5x - 6 -x - 6
Combine like terms:
BC = 4x - 12
To verify, we can add AB and BC to see if their sum is equal to AC.
(x + 6) + (4x - 12) = 5x - 6
If we are correct, this equation will be true.
x + 6 + 4x - 12 = 5x - 6
Combine like terms:
6 + 5x - 12 = 5x - 6
5x - 6 = 5x - 6
It's correct!
BC = 4x - 12. Final Answer.
Let me know if you have any questions about this! :)
Answer:
Total cost of equipment was $612. The remaining amount was spent on uniforms.
To find out how many uniforms were purchased,
Total cost of uniforms
=$912-$612
=$300
Number of uniforms purchased
=
$
300
$
25
=12
Step-by-step explanation:
We know that
g=3
r=2
b=5
total marbies=g+r+b------> 3+2+5----> 10
a) <span>probability that the first marble is red
P(red)=r/total marbies------------> 2/10-----> 1/5
b) </span><span>probability that the second marble is blue
in this case total marbles-------> 9
P(blue)=b/total marbles----------> 5/9
c) </span><span>the probability that the first marble is red and the second is blue
(1/5)*(5/9)=1/9
the answer is
1/9</span>
