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faltersainse [42]
3 years ago
13

In the reaction: pb + 2ag+ → pb2+ + 2ag, the oxidizing agent is

Chemistry
2 answers:
wariber [46]3 years ago
4 0

<u>Answer:</u> The oxidizing agent for the given reaction is Silver.

<u>Explanation:</u>

Oxidizing agent is defined as the agent which helps the other substance to get oxidized and itself gets reduced. It undergoes reduction reaction in which a substance gains electrons. The oxidation state of this substance gets reduced and the substance gets reduced.

Reducing agent is defined as the agent which helps the other substance to get reduced and itself gets oxidized. It undergoes oxidation reaction in which a substance looses its electrons. The oxidation state of this substance gets increased and the substance gets oxidized.

For the given chemical reaction:

Pb+2Ag^+\rightarrow Pb^{2+}+2Ag

The half reactions for the given above chemical reaction is:

Oxidation half reaction:  Pb\rightarrow Pb^{2+}+2e^-

Reduction half reaction: 2Ag^++2e^-\rightarrow 2Ag

As, lead is loosing electrons. So, it is getting oxidized and is considered as a reducing agent and silver is gaining electrons. So, it is getting reduced and is considered as an oxidizing agent.

Thus, the correct answer is silver.

shutvik [7]3 years ago
3 0
With reference to present question, following things may be noted
1) Oxidation is process of lose of electron. Atom//ion undergoing oxidation is refereed as reducing agent
2) Reduction is process of gain of electron. Atom/ion undergoing reduction is refereed as oxidizing agent.

in present system, Ag+ gain an electron to reduced to Ag. Therefore, Ag+ is an oxidizing agent. 
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2.(04.01 LC)
Mila [183]

Answer:

2KClO3 —> 2KCl + 3O2

The coefficients are 2, 2, 3

Explanation:

From the question given above, we obtained the following equation:

KClO3 —> 2KCl + 3O2

The above equation can be balance as follow:

There are 2 atoms of K on the right side and 1 atom on the left side. It can be balance by putting 2 in front of KClO3 as shown below:

2KClO3 —> 2KCl + 3O2

Now, the equation is balanced.

Thus, the coefficients are 2, 2, 3

8 0
3 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

#SPJ4

5 0
1 year ago
What was the key design change for hfc-134a a/c systems versus CFC 12 a/c systems
BabaBlast [244]
Answer is: key design change for HFC-134a A/C systems versus CFC-12 A/C systems was quick couple service fitting and that design reduce venting and mixing of refrigerants during service.

<span> Level of contamination is also reduced and the emission of refrigerants and greenhouse gases (sulfur dioxide, carbon dioxide) is also reduced.</span>

6 0
3 years ago
5 The apparatus shown below was set up. Give explanations for the following observations.
lana [24]

Answer:

hope it helps brainliest pls

Explanation:

3 0
2 years ago
An organic compound is composed of 38.7% C, 9.70% H, 51.6% O. The compound has a molecular formula mass of 62.0g/mol.
Tcecarenko [31]

<span>B)<span>C2H6O<span>2
</span></span></span>
First, convert each percentage to grams: 38.7g, 9.70g, and 51.6g. 
Next, calculate the number of moles of each element, based on the number of grams given.
C = 3.23 mol
H = 8.91 mol
O = 3.23 mol
Set up the ratio of moles of each element:
C3.34H9.70O3.23. Convert the decimals to whole numbers by dividing by the smallest subscript, 3.23.
The empirical formula is CH3O.
Now, compute the formula mass, which is 31. Finally, divide the molecular mass by the formula mass, 62/31 = 2. Multiple the subscripts by 2 to get the molecular formula.
5 0
3 years ago
Read 2 more answers
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