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faltersainse [42]
3 years ago
13

In the reaction: pb + 2ag+ → pb2+ + 2ag, the oxidizing agent is

Chemistry
2 answers:
wariber [46]3 years ago
4 0

<u>Answer:</u> The oxidizing agent for the given reaction is Silver.

<u>Explanation:</u>

Oxidizing agent is defined as the agent which helps the other substance to get oxidized and itself gets reduced. It undergoes reduction reaction in which a substance gains electrons. The oxidation state of this substance gets reduced and the substance gets reduced.

Reducing agent is defined as the agent which helps the other substance to get reduced and itself gets oxidized. It undergoes oxidation reaction in which a substance looses its electrons. The oxidation state of this substance gets increased and the substance gets oxidized.

For the given chemical reaction:

Pb+2Ag^+\rightarrow Pb^{2+}+2Ag

The half reactions for the given above chemical reaction is:

Oxidation half reaction:  Pb\rightarrow Pb^{2+}+2e^-

Reduction half reaction: 2Ag^++2e^-\rightarrow 2Ag

As, lead is loosing electrons. So, it is getting oxidized and is considered as a reducing agent and silver is gaining electrons. So, it is getting reduced and is considered as an oxidizing agent.

Thus, the correct answer is silver.

shutvik [7]3 years ago
3 0
With reference to present question, following things may be noted
1) Oxidation is process of lose of electron. Atom//ion undergoing oxidation is refereed as reducing agent
2) Reduction is process of gain of electron. Atom/ion undergoing reduction is refereed as oxidizing agent.

in present system, Ag+ gain an electron to reduced to Ag. Therefore, Ag+ is an oxidizing agent. 
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What is the number of moles in 15.0 g AsH3?
pentagon [3]

We are given with the mass of Arsine (AsH_{3}

The mass of arsine is 15g

there is a relation between moles, mass and molar mass of any compound which is

moles=\frac{mass}{molarmass}

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H

the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol

Let us calculate the moles as

moles=\frac{15}{77.92}=0.192mol


7 0
3 years ago
When does heat naturally move from cooler objects to warmer objects
Blizzard [7]
<span>Conduction occurs when two object at different temperatures are in contact with each other. Heat flows from the warmer to the cooler object until they are both at the same temperature. Conduction is the movement of heat through a substance by the collision of molecules. At the place where the two object touch, the faster-moving molecules of the warmer object collide with the slower moving molecules of the cooler object. </span>
8 0
4 years ago
Calculate the concentration (M) of sodium ions in a solution made by diluting 25.0 mL of a 0.765 M solution of sodium sulfide to
Yuri [45]

<u>Given:</u>

Concentration of Na₂S = 0.765 M

Volume of Na₂S solution = 25.0 ml = 0.025 L

Final total volume = 225 ml = 0.225 L

<u>To determine:</u>

The concentration of Na+ ions

<u>Explanation:</u>

# moles of Na₂S = 0.765 * 0.025 = 0.0191 moles

Based on the atomic stoichiometry of Na₂S-

# moles of Na⁺ ions = 2*0.0191 = 0.0382 moles

conc of Na⁺ ions = 0.0382 moles/ 0.225 L = 0.169 M

Ans: [Na⁺] = 0.169 M

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME I BEG YOU
VladimirAG [237]

The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
 
3.80 x 103 J

The relationship between volume and temperature of a gas, when pressure and moles of a gas are held constant, is: V*T = k.

FALSE

The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n = k. We could say then, that:
If the moles of gas are tripled, the volume must also triple.


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TRUE

If the vapor pressure of a liquid is less than the atmospheric pressure, the liquid will not boil.

TRUE


35 - AB

36 -  BD

33 - true

34 - False

20 - 6

21 - orthohombic


4 0
3 years ago
Name the following bases<br> -Ba(OH)2<br> - Ca(OH)2<br> -RbOH
Harman [31]

Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}

Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}

RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}

3 0
3 years ago
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