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2 years ago

Please Help ASAP! Simplify roots of negative numbers. Express your answer in simplified form.

Mathematics

1 answer:

Korolek [52]2 years ago

7 0

Answer:

$3i\sqrt2$

Step-by-step explanation:

We can rewrite the square root of negative 18 as $\sqrt{18} \cdot\sqrt{-1}$ . We can evaluate these two quantities separately. The square root of 18 can be factored to get 3 squared times 2. We can take the 3 out to get $3\sqrt2$ . Now, the square root of negative one can be rewritten as $i$ , so this is equal to $3i\sqrt2$

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If you were a colonist in the mid-1770s would you have stood with the Patriots or the Loyalists? Write an argumentative essay in

vekshin1

Answer:

I would have stood with the patriots because British soldiers forcefully entered their homes. They also ramped up taxes over a petty war with France because they couldnt pay it themselves.

The Loyalists were brainwashed to the British king, because they were rich and privileged. So they could pay the very high taxes. This meant these guys didn't actually know how the people felt.

The British also ramped up the price of tea, which the colonists loved, just to be petty because the Patriots did not want to be taxed. Back then, the British were very petty. Now they're just jaded.

But back to the essay: The Patriots had a good cause. They wanted to move on from something chaining them down. The Loyalists did not. And I would want to happily tar some tax collectors. Wouldn't you?

Step-by-step explanation:

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2 years ago

X = 3y - 6

Vlad1618 [11]

X = 3y - 6....so sub 3y - 6 in for x in the other equation

2(3y - 6) - 4y = 8
6y - 12 - 4y = 8
2y = 8 + 12
2y = 20
y = 20/2
y = 10

x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x = 24

solution is (24,10)

4 0

2 years ago

A point is on a circle if the distance from the center of the circle to the point is equal to the

QveST [7]

Radius. A circle is defined by points which are all the same distance from a point. This distance is the radius.

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2 years ago

Read 2 more answers

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. ex = 3 − 2x, (0

raketka [301]

Answer:

$f(0)=-2\\f(1)=e-1$

Step-by-step explanation:

According to intermediate value theorem, if a function is continuous on an interval $[a,b]$ , and if $k$ is any number between $f(a)$ and $f(b)$ , then there exists a value, $x=m$ , where $a$ , such that $f(m)=k$

In the given question,

Intermediate Value Theorem is used to show that there is a root of the given equation in the specified interval.

Here,

$f(x)=e^x-3+2x$

Put $x=0$

$f(0)=e^0-3+2(0)=1-3+0=-2$

Put $x=1$

$f(1)=e^1-3+2(1)=e-3+2=e-1$

3 0

2 years ago

B is the midpoint of AC. C is the midpoint of AD. Find the coordinates of B and D given the coordinates of A (-2,5) and the coor

GalinKa [24]

B= (3,6) and D= (18,9)

Step-by-step explanation:

To find the midpoint of two given points add X1 and X2 together, then divide by 2 to get the X value of the midpoint and do the same thing for the Y value. That will get you B. From there you can see to get from point A to point C you add 10 to the x value and add 2 to the y value. Because C is the midpoint just double what you had to add to get point D (add 20 to x and add 4 to y)

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2 years ago