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tigry1 [53]
2 years ago
12

Please Help ASAP! Simplify roots of negative numbers. Express your answer in simplified form.

Mathematics
1 answer:
Korolek [52]2 years ago
7 0

Answer:

3i\sqrt2

Step-by-step explanation:

We can rewrite the square root of negative 18 as \sqrt{18} \cdot\sqrt{-1}. We can evaluate these two quantities separately. The square root of 18 can be factored to get 3 squared times 2. We can take the 3 out to get 3\sqrt2. Now, the square root of negative one can be rewritten as i, so this is equal to 3i\sqrt2

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Solution q-2r=4<br> q+r=37
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Q-2r=4, therefore: q=4+2r.

Plug the value of q into q+r=37, so you get:

4+2r+r=37

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q-2r=4, but r=11, so:

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The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
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Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

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Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

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