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alex41 [277]
3 years ago
11

Explain how the heat and phase changes affects the environment? Give examples.(5-7 sentences)​

Chemistry
1 answer:
NeX [460]3 years ago
7 0
Energy is required to change the phase of a substance, such as the energy to break the bonds between molecules in a block of ice so it may melt.
During a phase change energy my be added or subtracted from a system, but the temperature will not change. The temperature will change only when the phase change has completed. No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a phase change). For example, consider water dripping from icicles melting on a roof warmed by the Sun. Conversely, water freezes in an ice tray cooled by lower-temperature surroundings. Energy is required to melt a solid because the cohesive bonds between the molecules in the solid must be broken apart so that the molecules can move around at comparable kinetic energies; thus, there is no rise in temperature.
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kherson [118]

Answer:

Explanation:

If this is a double replacement reaction or salt metathesis, then I have taken the liberty of including the symbol representing an aqueous solution, (aq), to the formulas in the equation written as CuCl2(aq)+2NaNO3(aq)→Cu(NO3)2(aq)+2NaCl(aq).

In order for a double replacement reaction to occur, one of the products must be a solid precipitate (a salt), an insoluble gas, or water. Since all species are in aqueous solution, none of these products occur, which means there is no reaction. The result is an aqueous solution containing Cu2+, Cl−, Na+, and NO3− ions.

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This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.

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3 0
3 years ago
HELP!!!
Volgvan
<h3><u>Answer;</u></h3>

pH = 6.34

<h3><u>Explanation;</u></h3>

pH is given as -log{H+]

But;

pH + pOH = 14

However;

pOH = -log [OH-]

[OH-] =  2.20 × 10−8 M

Thus;

pOH = -log (2.20 × 10−8 M)

        = 7.66

But;

pH = 14 - pOH

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