A rectangular lot has an area of 240m. What is the width of the lot if it requires 64m of fencing materials to enclosed it ?.

TEA [102]

You can solve this by multiplying each numerator by the answer choices and trying to divide them. I can't get the fraction maker to work at the moment, so I'll write the calculations on a separate attachment.

As you can see, the only choice that works to eliminate both fractions is the fourth choice, 50x.

8 0

3 years ago

What is 100000000000000x234500000020000030040040

Pavlova-9 [17]

Answer:

234500000020000000000000000

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which is the equation of a line that has a slope of -7 and a Y intercept of 2

padilas [110]

Answer:

y = -7x + 2

Step-by-step explanation:

3 0

3 years ago

Daniella is making 2/3 of a recipe. the full recipe calls for 3 1/2 cups of flour. how many cups of flour should Danielle use?

kupik [55]

2 $\frac{1}{3}$ cups of flour

We require to find $\frac{2}{3}$ of 3 $\frac{1}{2}$

change the mixed number to an improper fraction and of to multiply

3 $\frac{1}{2}$ = $\frac{7}{2}$

$\frac{2}{3}$ × $\frac{7}{2}$

= $\frac{2(7)}{3(2)}$ = $\frac{14}{6}$ = $\frac{7}{3}$ = 2 $\frac{1}{3}$

4 0

3 years ago

In 2009, the Southeastern Conference (SEC) commissioner set a goal to have greater than 65% of athletes that are entering freshm

dangina [55]

Answer:

$z=\frac{0.7 -0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}=1.048$

$p_v =P(z>1.048)=0.147$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 5% of significance the proportion of people who graduate in 6 years is not significantly higher than 0.65 .

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X=70 represent the number of people who graduate in 6 years

$\hat p=\frac{70}{100}=0.7$ estimated proportion of people who graduate in 6 years

$p_o=0.65$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.65:

Null hypothesis: $p \leq 0.65$

Alternative hypothesis: $p >0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.7 -0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}=1.048$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =P(z>1.048)=0.147$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 5% of significance the proportion of people who graduate in 6 years is not significantly higher than 0.65 .

7 0

3 years ago