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Kryger [21]
3 years ago
15

Bill wants to rent a car.Rental Company A charges $35 per day plus $0.10 per mile driven.Rental Company B charges $25 per day pl

us $0.15 per mile. How many miles driven will the price charged by each company be the same.
Mathematics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

m = 200 miles

Step-by-step explanation:

Rental Co. A:  A(m) = $35 + ($0.10/mile)(m), where m is the number of miles driven

Rental Co. B:  B(m) = $25 + ($0.15/mile)(m)

Set these two dollar amounts equal to each other and solve for m:

$25 + ($0.15/mile)m = $35 + ($0.10/mile)(m).  Combine like terms, obtaining:

($0.05/mile)m = $10; then m = ($10) / ($0.05/mile), or 200 miles.

The price charged by the two companies would be the same when the car has been driven 200 miles.

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Answer:

0.286

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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
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keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

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\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7

8 0
3 years ago
Read 2 more answers
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I think it would cost $13,400

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<span>
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Answer:

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