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Gala2k [10]
3 years ago
7

Rewrite the following expressions as a single logarithm. 3 − 2 log2 − 5 log2 y

Mathematics
1 answer:
lara [203]3 years ago
3 0

Step-by-step explanation:

<h3>3-2log 10(2) -5 log 10(2y)</h3><h3>log 10 (10)3 -2 log 10 (2) -5 log 10 (2y)</h3><h3>3-2 log 10 (2) -5 log 10 (2y)</h3><h3>3+log 10 (2-^2) -5 log 10 (2y)</h3><h3>3+log 10 (2-^2)+ log 10 {(2y)-^5}</h3><h3>3+log 10 (2-^2 ×(2y)-5)</h3><h3>3+ log 10 (2^-2 × 2^-5 y^-5)</h3><h3>3+ log 10 (2^-2×2^-5 ×1/y^5</h3><h3>3+ log 10 (2^-7/y^5)- 3+ log 10 (1/y^5×2^7)</h3><h3>3+ log 10 (1/y^5×128)</h3><h3>3+log 10 (1/128 y^5)</h3><h3>3+log 10 {(128 y^5)^-1)</h3><h2>3- log 10 (128 y^5) </h2>

<h3 /><h3 /><h3 />
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