11 please ..........

Mathematics

1 answer:

n200080 [17]2 years ago

4 0

0.8,0.0008 in is the answer in inches i know how u feel

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Please help me with this question

Vladimir [108]

Answer: 20

Step-by-step explanation:

numbers belonging to the figure on the left are 2.5 times less than on the right so to find x multiply 8 by 2.5 and that is 20

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2 years ago

Express the vector ModifyingAbove Upper P 1 Upper P 2 with right arrowP1P2 in the form Bold v equals v 1 Bold i plus v 2 Bold j

Tatiana [17]

Answer:

$\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

Step-by-step explanation:

$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

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3 years ago

A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hot dogs and 13 dozen

kicyunya [14]

Answer:

1 hot dog costs $0.75

1 bratwurst costs $1.35

Step-by-step explanation:

Let x and y be the price per dozen of hot dogs and bratwursts respectively.

The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60

8x + 13y = 282.60

The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00

10x + 15y = 333

and we have the linear system

which can be written in matrix form as

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)\left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{c}282.60\\333\end{array}\right)$

The solution would be given by

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}\left(\begin{array}{c}282.60\\333\end{array}\right)$

We have

$\bf \left(\begin{array}{cc}8&13\\10&15\end{array}\right)^{-1}=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)$

hence

$\bf \left(\begin{array}{c}x\\ y\end{array}\right)=\left(\begin{array}{cc}-3/2&13/10\\1&-4/5\end{array}\right)\left(\begin{array}{c}282.60\\333\end{array}\right)=\left(\begin{array}{c}9\\ 16.2\end{array}\right)$