Answer:
(507.05, 592.95)
Step-by-step explanation:
Given data:
sample mean = $550, sample standard deviation S = $60.05
95% confidence interval , n = 10
For 95% confidence interval for the mean
mean ± M.E.
where M.E. is margin of error = 
Substituting the values in above equation

= 2.62×18.99
=42.955
= 550±42.95
=(507.05, 592.95)
Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
The correct answer is -3.6. Hope this helps!!
Answer: 11 units
Step-by-step explanation: Just took it on edg.
This is an application of integral calculus. The area under a curve could be expanded to determine the volume of a sphere if you revolve this area about a certain axis or a certain line. It should be given that the area is in the shape of either a half-circle or a quarter circle, so that it should form a sphere when revolved.