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Jobisdone [24]
2 years ago
15

Iupac names of the following ​

Chemistry
1 answer:
Nadusha1986 [10]2 years ago
6 0
It’s blurry.... try again
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Cassidee walks 1-mile north and then turns and walks 2 miles west. Distance Displacement
Gemiola [76]

Answer:

3 miles?

Explanation:

if you walk one mile North and then turn and walk another two miles you walk 3 miles and then turn around and walk back in the same direction you would end backup at the one-mile Mark he began. So three miles there two miles back

4 0
2 years ago
If a hard water solution is saturated with calcium carbonate, what volume of the solution has to evaporate to deposit 1.00×102 m
olasank [31]
I think the Ksp for Calcium Carbonate is around 5×10⁻⁹
(I don't know if this is the Ksp value that you use because I read somewhere that this value can vary.  You should probably check with your teacher with what Ksp value they want you to use)

the equation for the dissociation CaCO₃ in water is CaCO₃(s)⇄Ca²⁺(aq)+CO₃²⁻(aq) which means that the concentration of Ca²⁺ is equal to the concentration of CO₃²⁻ in solution.  For every molecule of CaCO₃ that dissolves, one atom of Ca²⁺ and one molecule of CO₃²⁻ is put into solution which is why the concentrations are equal in solution. 

Since Ksp=[Ca²⁺][CO₃²⁻] and we know that [Ca²⁺]=[CO₃²⁻] we can rewrite the equation as Ksp=x² since if you say that [Ca²⁺]=[CO₃²⁻] when you multiply them together you get the concentration squared (I am calling the concentration x for right now).

when solving for x:
5×10⁻⁹=x²
x=0.0000707
Therefore [Ca²⁺]=[CO₃²⁻]=0.0000707mol/L which also shows how much calcium carbonate is dissolved per liter of water since the amount of Ca²⁺ and CO₃²⁻ in solution came from the calcium in a 1 to 1 molar ratio as shown in the equation (the value we found for x is the molar solubility of calcium carbonate).

Using the fact that the molar mass of calcium carbonate is 100.09g/mol you can use dimensional analysis as fallows:
(0.0000707mol/L)(100.09g/mol)=0.007077g/L
That means that there is 0.007077g of Calcium carbonate that can precipitate out of 1L of water.

since the question is asking for how much water needs to be evaporated to precipitate 100mg (0.1g) of Calcium you have to do the fallowing calculation:
(0.1g)/(0.007077g/L)=14.13L of water.
14.13L of water needs to evaporate in order to precipitate out 100mg of calcium carbonate

These types of questions can get long and confusing so I bolded parts that were important to try to guide you through it more easily.

I hope this helps.  Let me know if anything is unclear.
6 0
3 years ago
IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath
vaieri [72.5K]

Answer:

I think it is 0.00192

Explanation:

28.795705

15000

=0.00192

8 0
3 years ago
Zinc + Hydrogen Chloride <br> What is proof of a chemical reaction?
maria [59]

Answer:

zncl2. . . . . . . . . . . . . . . .

7 0
3 years ago
Read 2 more answers
Which of the following would be most likely to experience strong intermolecular forces?
ryzh [129]

Answer:

The correct answer is D

Explanation:

Just took quiz

6 0
3 years ago
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