The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the following formula:
p = m/v
Where;
- p = density
- m = mass
- v = volume
According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.
1.43g/L = 6.4g/V
Volume of O2 = 6.4 ÷ 1.43 = 4.48L
Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.
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The nucleus is effected
Explanation: The nucleus is the main part of it gets weak they all get weak
Answer:
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Answer:
H₂O
Explanation:
H₂O is the chemical formula of water.
Water is regarded as a "universal solvent". The reason behind this is the property of the water. Water is a solvent that can dissolve a variety of substances in itself. Any other liquid cannot dissolve the number of substances that the solvent water can. The reason behind being the universal solvent is the chemical composition and physical characteristics of water.
Answer:
Mass of water produced= 1.8 g
Explanation:
Given data:
Mass of water produced = ?
Mass of butane = 1.36 g
Mass of oxygen = excess
Solution:
Chemical equation:
2C₄H₁₀ +13 O₂ → 8CO₂ + 10H₂O
Number of moles of butane:
Number of moles = mass/molar mass
Number of moles = 1.36 g/ 58.12 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of butane with water.
C₄H₁₀ : H₂O
2 : 10
0.02 : 10/2×0.02 = 0.1 mol
Mass of water produced:
Mass = molar mass × molar mass
Mass = 0.1 mol × 18 g/mol
Mass = 1.8 g
