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Nonamiya [84]
4 years ago
14

A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the d

ifferent levels of biodiversity for the four ecosystems as shown in the table below.
Genetic Diversity Species Diversity Habitat Diversity
Ecosystem A Low Low Medium
Ecosystem B Medium High Medium
Ecosystem C High Low Low
Ecosystem D Medium Low High
Based on the information above, which ecosystem would most likely recover the fastest from a natural disruption?


Ecosystem A

A

Ecosystem B

B

Ecosystem C

C

Ecosystem D
Chemistry
1 answer:
Contact [7]4 years ago
5 0

Answer: ecosystem a

Explanation:

have a good day

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Can someone please help me on #17? I don’t get it :(
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Given is the specific heat of water equal to 4.18 Joule per gram per *C.

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Have a look at pic for answer

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3 years ago
Which organisms are the best example of producers in a food web? A. zooplankton B. krill C. killer whales D. marine phytoplankto
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3 years ago
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Which atom in the ground state has a partially filled second electron shell?
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Therefore the second energy shell is partially filled. This is the correct answer

3. K - electron configuration is 2,8,8,1
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4 0
3 years ago
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What is the net ionic equation for the reaction that occurs when aqueous copper(II) sulfate is added to excess 6-molar ammonia?a
Karolina [17]

Answer:

c. 2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

Explanation:

A net ionic equation is a chemical equation that list only the species that are involved in the reaction.

The reaction of ammonia with copper(II) sulfate CuSO₄ in water is:

2NH₃ + 2H₂O  + CuSO₄ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

In an ionic equation, salts are written as ions, that means CuSO₄ must be written as Cu²⁺ + SO₄²⁻. That is:

2NH₃ + 2H₂O  + Cu²⁺ +<u> SO₄²⁻</u> → Cu(OH)₂(s) + 2NH₄⁺ + <u>SO₄²⁻</u>

As in a net ionic equation you must list only the species involved in the reaction (The underlined species don't react), the net ionic equation is:

<em>c</em>. <em>2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺</em>

<em></em>

I hope it helps!

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