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Bas_tet [7]
2 years ago
15

Bauxite must go through two processes to produce aluminum metal. The yield of the Bayer process, which extracts aluminum oxide f

rom bauxite, is 40 percent The yield of converting aluminum oxide to aluminum is 50 percent. Determine the yield in grams of aluminum from one cubic meter of bauxite ore.
Chemistry
1 answer:
Mashcka [7]2 years ago
3 0

The yield of aluminium obtained from 1 m^3 of bauxite is 419810 g

<h3>What is a Percent yield</h3>

A percent yield of a substance measures the amount of the substance actually obtained as a percentage ratio of expected yield.

Percent yield = actual yield / expected yield × 100%

<h3>How to calculate the mass of aluminium obtained from bauxite </h3>

From the data given:

40 % of the bauxite is converted to aluminium oxide.

Volume of bauxite = 1 m^3

40 % of 1 m^3 = 0.4 m^3

volume of aluminium oxide = 0.4 m^3

density of aluminium oxide = 3965 kg/m^3

  • Using mass = density × volume

mass of aluminium oxide = 0.4 × 3965 kg

mass of aluminium oxide = 1586 kg

Formula of aluminium oxide is Al203

molar mass of aluminium oxide = 102 g

  • percentage mass of aluminium in one mole of aluminium oxide = mass of aluminium / mass of aluminium oxide × 100 %

Percentage mass of aluminium in aluminium oxide = 54/102 × 100

Percentage mass of aluminium in aluminium oxide = 52.94 %

Expected mass of aluminium from aluminium oxide = 52.94 × 1586

Expected mass of aluminium = 839.62 kg

Actual yield = 40 % × 839.62

Actual yield of aluminium = 419.81 kg

mass of aluminium in grams = 419810 g

Therefore, mass of aluminium obtained from 1 m^3 of bauxite is 419810 g

Learn more about percent yield at: brainly.com/question/8638404

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An aqueous solution contains 0.29 M of benzoic acid (HA) and 0.16 M of sodium benzoate (A-). If the pH of this solution was meas
Inga [223]

Answer:

pKa = 4.89.

Explanation:

We can solve this problem by using the <em>Henderson-Hasselbach equation</em>, which states:

pH = pKa + log \frac{[A^-]}{[HA]}

In this case [A⁻] is the concentration of sodium benzoate and [HA] is the concentration of benzoic acid.

We <u>input the given data</u>:

4.63 = pKa + log \frac{0.16}{0.29}

And <u>solve for pKa</u>:

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3 0
3 years ago
How many grams of sodium phosphate are formed by the reaction of 10 g of sodium with phosphoric acid?
Norma-Jean [14]

Answer:

23.8g of sodium phosphate are formed

Explanation:

Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:

3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂

<em>3 moles of sodium produce 1 mole of sodium phosphate</em>

<em />

To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:

<em>Moles Na -Molar mass: 22.99g/mol-</em>

10g * (1mol / 22.99g) = 0.435 moles Na

<em>Moles Na₃PO₄:</em>

0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄

<em>Mass Na₃PO₄ -Molar mass: 163.94g/mol-</em>

0.145 moles Na₃PO₄ * (163.94g/mol) =

<h3>23.8g of sodium phosphate are formed</h3>
8 0
2 years ago
How many atoms are in 3.0 moles of NA?
Vanyuwa [196]

Avogadro's number is the number of atoms in one mole of a substance. The number is 6.022 x 10^23 atoms/mol. So, if you have 1 mole of carbon atoms, there will be 6.022 x 10^23 atoms in that sample.

Hope this helps

5 0
3 years ago
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