Answer:
London Dispersion Force<span> is the strongest interparticle force in a sample of Kr.
Explanation:
Krypton belongs to Noble Gases. They exists in monoatomic form as they are inert in nature and are very less reactive. So, as there is no polarity in Krypton so it will fail to create either Dipole-Dipole or Hydrogen Bond Interactions between its atoms. While, London Dispersion Forces or Van Der Waals forces can exist between Kr atoms. When Kr atoms approaches one other they create Instantaneous dipole. This</span> Instantaneous dipole induces dipole in second Kr atom and the process starts propagating. Hence, interactions are generated between Kr atoms.
Answer:
ten atoms of hydrogen are present in one mole of caffeine.
Explanation:
Molecular formula of caffiene is given which is C3H10N4O2. It clearly shows that ten atoms of hydrogen are present. One mole is amount equal to one molecular weight of a molecule which is derived from molecular formula. So as moecular formula has ten atoms of hydrogen, one mole of caffeine has 10 atoms of hydrogen.
Answer:
YUHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
Explanation:
FRRL ITS 3
Answer:
0.0038 M
Explanation:
Hardness of the water is generally due to the presence of
in water.
At equivalence point
Moles of
= Moles of EDTA
Considering
![Molarity_{Ca^{2+}}\times Volume_{Ca^{2+}}=Molarity_{EDTA}\times Volume_{EDTA}](https://tex.z-dn.net/?f=Molarity_%7BCa%5E%7B2%2B%7D%7D%5Ctimes%20Volume_%7BCa%5E%7B2%2B%7D%7D%3DMolarity_%7BEDTA%7D%5Ctimes%20Volume_%7BEDTA%7D)
Given that:
![Molarity_{EDTA}=0.020\ M](https://tex.z-dn.net/?f=Molarity_%7BEDTA%7D%3D0.020%5C%20M)
![Volume_{EDTA}=4.86\ mL](https://tex.z-dn.net/?f=Volume_%7BEDTA%7D%3D4.86%5C%20mL)
![Volume_{Water\ or\ Ca^{2+}}=25.00\ mL](https://tex.z-dn.net/?f=Volume_%7BWater%5C%20or%5C%20Ca%5E%7B2%2B%7D%7D%3D25.00%5C%20mL)
So,
![Molarity_{Ca^{2+}}\times 25=0.020\times 4.86](https://tex.z-dn.net/?f=Molarity_%7BCa%5E%7B2%2B%7D%7D%5Ctimes%2025%3D0.020%5Ctimes%204.86)
![Molarity_{Ca^{2+}}=0.0038\ M](https://tex.z-dn.net/?f=Molarity_%7BCa%5E%7B2%2B%7D%7D%3D0.0038%5C%20M)