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tatuchka [14]
3 years ago
13

What effect does a quadrupling of the mass have upon the acceleration of the object

Chemistry
1 answer:
netineya [11]3 years ago
8 0
The state in which all of the external forces acting upon an object are balanced; there is no acceleration. friction ..... quadrupling. doubling distance and quadrupling mass has the overall effect of the force
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Help me please thank you
meriva
It would be -1 charge
5 0
4 years ago
Which of the following lends itself to the use of a descriptive method? a. Jonathan would like to develop a hypothesis regarding
Marianna [84]

Answer:

a. Jonathan would like to develop a hypothesis regarding the role of parental expression of affection in reducing toxic stress in early childhood.

Explanation:

A descriptive method is commonly known as a research method for describing the properties or features of the research area being investigated. Descriptive research is usually conducted by studying the trends of the phenomenon without changing the value of any variable in the system. Thus, the correct answer is option a.

7 0
3 years ago
Which of the following is an oxidation-reduction reaction?
KiRa [710]

C₆H₁₂O₆ + 6 O₂ ⇒ 6 CO₂ + 6 H₂O

This is an oxidation-reduction reaction, because oxidation numbers of carbon and oxygen atoms are different than before reaction.

(-_-(-_-)-_-)

3 0
3 years ago
True or false, the four units that must always be used when using the ideal gas law are liters, atm, Kelvin, and grams
maksim [4K]

Answer:

False  grams is not used

Explanation:

IDEAL GAS LAW

The ideal gas law states that PV = NkT, where P is the absolute pressure of a gas, V is the volume it occupies, N is the number of atoms and molecules in the gas, and T is its absolute temperature.  

It is necessary to use Kelvin for the temperature and it is conventional to use the SI unit of liters for the volume. However, pressure is commonly measured in one of three units:  kPa ,  atm , or  mmHg . Therefore,  R  can have three different values.

3 0
3 years ago
use the gizmos to mix 200 G of copper at 100 C with 1000 g of water at 20 C whatis the final temperature
ziro4ka [17]

Answer:

Explanation:

mass of copper = 200 g at temperature 100°C

mass of water = 1000 g at 20⁰C

Let the final temperature be T .

specific heat of copper = .385 J per gram

specific heat of water = 4.182 J per gram

heat lost = mass x specific heat x fall of temperature

heat lost by copper

= 200 x .385 x ( 100 - T )

heat gained by water

= 1000 x 4.182 x ( T - 20 )

heat lost by copper = heat gained by water

200 x .385 x ( 100 - T )  = 1000 x 4.182 x ( T - 20 )

7700 - 77 T = 4182 T - 83640

4259 T  = 91340

T = 21.44⁰C .

5 0
3 years ago
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