The solubility of potassium chloride in at room temperature is approximately 34 g per 100 g of water. Therefore, the maximum amount that could be dissolved would be 34/100 ( 200) = 68 g of KCl. When more than this amount is added, excess potassium would not dissolve forming crystals in the solution.
Answer:
1 (348) (D2) = 273 (2.05) (0.805) D2= 1.29 g/L
Explanation:
Answer:
It emits hydrogen sulfide...smells like rotten eggs..
ty:)pls let me know whether this is ryt:D
Answer:
3.02 X1023 atoms Ag limol. - - 0.50 1 moles. 6.02241023 atoms.
