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EastWind [94]
2 years ago
6

What is it's momentum?

Physics
1 answer:
GenaCL600 [577]2 years ago
6 0
  • Mass of the truck (m) = 30000 Kg
  • Velocity (v) = 25 m/s
  • Let the momentum be p.
  • We know, momentum = mass × velocity
  • Therefore, the momentum of the truck (p)
  • = mv
  • = (30000 × 25) Kg m/s
  • = 750000 Kg m/s

<u>Answer</u><u>:</u>

<u>The </u><u>momentum</u><u> </u><u>of </u><u>the </u><u>truck </u><u>is </u><u>7</u><u>5</u><u>0</u><u>0</u><u>0</u><u>0</u><u> </u><u>Kg </u><u>m/</u><u>s.</u>

Hope you could understand.

If you have any query, feel free to ask.

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Why sun is known as main or ultimate<br>source of energy?( please in short answer)​
erastova [34]

Answer:

because of the heats came from to ultraviolet trnasform and i thankyou

6 0
3 years ago
Question: How is a triple beam balance used to find mass?1. Observe: The riders have masses of 10 grams (top), 100 grams (middle
ozzi

Answer:

1) For the weight to be correct, the pointer must be below the reference (zero) or in it

2)  mass greater than 300 g leave the pointer below the reference,

3) put weight on the other arms the pointer gets closer to the reference

Explanation:

1) A three-arm scale is used to determine the weight of a body by successive approximations, starting with the arm with the greatest mass (middle), when the pointer is close to zero without going over, weights are placed on the second arm (above ) weight is placed to bring the pointer closer to the reference without going over and when it is used the arm with the lowest mass is used (below) with this one, masses are placed until reaching the reference,

Taking all the jinetillos placed the total weight, the product of the position of the jinetillo by the precision of the arm and then the three values ​​are added.

In the example given, the jinetillo is placed in position 3 of the 100 arm, so the weight is 300 gr.

For the weight to be correct, the pointer must be below the reference (zero) or in it

2) objects with a mass greater than 300 g leave the pointer below the reference, it must be completed with the other two arms to reach the correct weight

3) when you put weight on the other arms the pointer gets closer to the reference

4 0
4 years ago
Name 2 forces acting on an object at rest Only need 1 got gravity
mote1985 [20]

You mean like a box sitting on a table.

One force is the force of gravity, pulling downward on the box.

Now, you know that the forces acting on the box must be balanced, because
if they're not, then the box would be accelerating.  But it's just sitting there, so
there must be some other force, just exactly the right strength and direction to
exactly cancel the force of gravity on the box, so that the net force on it is zero.

The other force is the force of the table pushing upward on the box.  It's called
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7 0
3 years ago
What state of matter takes the shape and volume of its container, like the steam coming from a pot A) gas B) liquid Eliminate C)
Gnoma [55]

Ummm gas takes the shape and volume of its container, but I don't know about plasma. Solids definitely don't, and liquids don't change their volumes. So I would say gas. :)

6 0
3 years ago
Read 2 more answers
A metal sphere with a mass of 0.026 kg rolls along a friction-less surface at 3.7 m/s and strikes a stationary sphefe having a m
zubka84 [21]

The force applied to the second ball by the first ball is 6.734 × 10^-4 N.

<h3>What is impulse of force?</h3>

The impulse of force is defined as the sum of the average force and the duration it is applied.

If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.

Given that:  mass of a metal sphere: m = 0.026 kg.

Initial speed of the sphere: u = 3.7 m/s.

When the sphere stops completely, its change in momentum = mu - 0

= 0.026×3.7 N-s.

= 0.0962 N-s.

As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied  to the second ball =

change in momentum of 1st ball × time of contact

= 0.0962 × 0.007 N

= 0.0006734 N

= 6.734 × 10^-4 N.

Hence,  the force applied  to the second ball is  6.734 × 10^-4 N.

Learn more about impulse force here:

brainly.com/question/29787329

#SPJ1

7 0
1 year ago
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