Answer:
metals,nonmetals, and inert gases
Explanation:
Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC = 
Q' = + 42 nC = 
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:



Now,
Electric field at the mid-point due to charge Q' is given by:



Now,
The net Electric field is given by:


Na is in the first column on the periodic table so therefore it would have 1 valence electron
D 1
Answer:
V initial = 29.4 m.s²
Explanation:
( Using the laws of motion)
V final = V initial + Acceleration × time
0 = V initial + ( -9.8)(3)
29.4 = V initial
* I took upward as positive that's why I substituted -9.8 *
* for V final we know that at maximum height the ball is not moving thats why is = 0 *
Using energy.
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