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____ [38]
4 years ago
11

How do darwin finches illistrate the thoery of natural selection

Physics
1 answer:
cricket20 [7]4 years ago
5 0
As they evolved and adapted, those of the fittest survived to reproduce. Those that did not adapt, died.
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What are the condition required for reverberation?​
Luda [366]

Answer:

Reverberation is created when a sound produced in a sapce is reflected off surfaces, like walls, teh floor or the ceiling. ... The time it takes for this sound in the space to decrease in volume down to 60 decibels (practically silence) after the sound source is extinguished is its reverberation time.

8 0
3 years ago
You are conducting an experiment inside a train car that may move along level rail tracks. A load is hung from the ceiling on a
katrin2010 [14]

Answer:

b

c

e

h

Explanation:

Note that the swing direction was not giving in the question and direction could be sideways (in a turn) or in a track or both

The question show something in common ...acceleration

So let's look at the statements and pick the correct ones

a is false while b is correct as the train is accelerating

c is correct. The train is accelerating even thou the speed could not be ascertained

d is false and not feasible as the train is accelerating

e is true as the train maybe moving at a constant speed in a circle

f is false. This could be constant velocity in a circle. Same as g (false)

h is true. It's accelerating

7 0
3 years ago
Round the following off to required number of significant figures.
Stells [14]

Answer:

140

hope this helps

have a good day :)

Explanation:

4 0
3 years ago
Read 2 more answers
The process of making alloys involves(Cooling, Heating or mixing) pure metals to remove impurities. Then the pure metals are(bro
ANEK [815]
<span>The process of making alloys involves ( Heating ) pure metals to remove impurities. Then the pure metals are(mixed) with other components. </span><span>An </span>alloy<span> is a mixture of metals or a mixture of a metal and another element. </span>Alloys<span> are defined by a metallic bonding character.</span>
8 0
3 years ago
Read 2 more answers
Two point charges are on the y-axis. A 3.0 µC charge is located at y = 1.15 cm, and a -2.28 µC charge is located at y = -2.00 cm
Ghella [55]

Answer:

Total electric potential, V=1.32\times 10^6\ volts

Explanation:

It is given that,

First charge, q_1=3\ \mu C=3\times 10^{-6}\ C

Second charge, q_2=-2.28\ \mu C=-2.28\times 10^{-6}\ C

Distance of first charge from origin, r_1=1.15\ cm=0.0115\ m

Distance of second charge from origin, r_2=2\ cm=0.02\ m

We need to find the total electric potential at the origin. The electric potential at the origin is given by :

V=\dfrac{kq_1}{r_1}+\dfrac{kq_2}{r_2}

V=k(\dfrac{q_1}{r_1}+\dfrac{q_2}{r_2})

V=9\times 10^9(\dfrac{3\times 10^{-6}}{0.0115}+\dfrac{-2.28\times 10^{-6}}{0.02})

V = 1321826.08 V

or

V=1.32\times 10^6\ volts

So, the total electric potential at the origin is 1.32\times 10^6\ volts. Hence, this is the required solution.

3 0
3 years ago
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