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SIZIF [17.4K]
2 years ago
13

Which of the following would increase the elastic force acting on that object

Physics
2 answers:
olga_2 [115]2 years ago
4 0

Answer:

Which of the following would increase the elastic force acting on that object? Moving a spring to an unstretched position. Compressing a spring twice as much as its starting position.

Explanation:

never [62]2 years ago
4 0

Answer:

Moving a spring to an unstretched position. Compressing a spring twice as much as its starting position.

Explanation:

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3 years ago
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sineoko [7]

Answer:

2,500 watts

Explanation:

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3 years ago
A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless trac
liraira [26]

Answer:

2.7 s

Explanation:

The period of the motion of a massless loaded spring is given by

T = 2\pi\sqrt{\dfrac{m}{k}}

where m is the mass of the load and k is the force or spring constant.

Using values in the question and converting to appropriate units,

T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}

5 0
3 years ago
Read 2 more answers
Susie blows up a balloon. First, she places the balloon in a bucket of ice water. She observes the balloon. She then removes the
Alexus [3.1K]
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6 0
2 years ago
A wrecking ball is hanging at rest from a crane when suddenly the cable breaks. The time it takes for the ball to fall halfway t
Naddik [55]

Answer:

1.697s

Explanation:

We use the second equation of free fall under gravity as follows;

h=ut+\frac{1}{2}gt^2...............(1)

Since  the ball fell freely, u = 0m/s, therefore equation (1) reduces to

h=\frac{1}{2}gt^2...............(2)

Given that h is the total height the ball falls through in time t seconds.

However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of \frac{h}{2} in 1.2s. Hence we can write the following, given that g=9.8m/s^2;

\frac{h}{2}=\frac{1}{2}*9.8*1.2^2\\hence\\h=9.8*1.2^2\\h=14.112m

We can now proceed to find the time t for which it falls through h = 14.112m as follows;

14.112=\frac{1}{2}*9.8*t^2\\14.112=4.9t^2\\t^2=\frac{14.112}{4.9}\\t^2=2.88\\t=\sqrt{2.88} \\t=1.697s

8 0
3 years ago
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