<h2>
The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3 s
Substituting
s = ut + 0.5 at²
s = 0 x 3 + 0.5 x 9.81 x 3²
s = 44.145 m
The seagull's approximate height above the ground at the time the clam was dropped is 4 m
It depends on mass and distance.
Answer:
4847.94844926 kg/m³
Explanation:
= Actual density of cube = 1900 kg/m³
= Density change due to motion
v = Velocity of cube = 0.92c
c = Speed of light = 
Relativistic density is given by

The cube's density as measured by an experimenter in the laboratory is 4847.94844926 kg/m³
Here in this question as we can see there is no air friction so we can use the principle of energy conservation


now here we know that



now plug in all values in above equation

divide whole equation by mass "m"



so height of the ball from ground will be 1.35 m