Answer:
a)
Explanation:
a) the cross-sectional area of the hose would be the square of radius times pi. And since the sectional radius is half of its diameter d. We can express the cross-sectional area A1 in term of diameter d1
Which term describes a lens with a surface that curves outward like the exterior of a sphere?
1 answer:
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Answer:
The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²
Explanation:
Given;
radius of the turnable, r = 60 cm = 0.6 m
rotational kinetic energy, E = 0.25 J
angular speed of the turnable, ω = 45 rpm
The rotational kinetic energy is given as;
where;
I is the moment of inertia about the axis of rotation
ω is the angular speed in rad/s
Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²