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Liono4ka [1.6K]
3 years ago
11

A concave mirror of focal length 10cm forms an inverted image of 40cm from the mirror and 4cm high. Determine the position and s

ize of the object by scale drawing and by calculation
​
Physics
1 answer:
Alika [10]3 years ago
7 0

The equation of the constructor of the geomeric optics allows to find the results for the distance and size of the objects are:

  • Distance from the mirror to the object is:  p = 13.3 cm
  • The height of the object is: h = 1.33 cm

The equation of the constructor of geometric optics describes the position of objects and their images for mirrors and lenses.

       \frac{1}{f} = \frac{1}{p} + \frac{1}{q}  

Where f is the focal length, p and q are the distances to the object and the image, respectively.

They indicate the focal length f = 10 cm, the distance to the image q = 40 cm, that the height s h ’=  4 cm.  In the attachment we see a scheme of the system.

Let's find the distance to the object.

        \frac{1}{p\frac{x}{y} } = \frac{1}{f} - \frac{1}{q} \\\frac{1}{p}  = \frac{1}{10} - \frac{1}{40}\\\frac{1}{p} =    0.075

       p = 13.3 cm

The magnification in the ratio of image size to object size.  The image is inverted so its height is negative.

        m = \frac{h'}{h} = - \frac{q}{p}\\h = - \frac{p}{q} \ h'\\h = - \frac{13.3}{40}\ (-4)

        h = 1.33 cm

In conclusion using the equation of the constructor we can find the results for the distance and size of the objects are:

  • Distance from the mirror to the object is  13.3 cm
  • The height of the object is 1.33 cm

   

Learn more here: brainly.com/question/14314471

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