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ololo11 [35]
3 years ago
8

Astronomers are comparing two stars that are known to have the same luminosity. Star A is observed to be 4 times brighter than s

tar B. How far away is Star A compared to Star B?
Physics
1 answer:
GaryK [48]3 years ago
7 0
The answer is two3988140
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V ( initial ) = 20 m/s
h = 2.30 m
h = v y * t + g t ² / 2
d = v x * t
1 ) At α = 18°:
v y = 20 * sin 18° = 6.18 m/s
v x = 20 * cos 18° = 19.02 m/ s
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4.9 t² + 6.18 t - 2.30 = 0
After solving the quadratic equation ( a = 4.9, b = 6.18, c = - 2.3 ):
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t = 0.3 s
d 1 = 19.02 m/s * 0.3 s = 5.706 m
2 ) At  α = 8°:
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2.3 = 2.78 t + 4.9 t² 
4.9 t² + 2.78 t - 2.3 = 0
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GOOD LUCK AND HOPE IT HELPS U
6 0
3 years ago
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