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3 years ago

8

Astronomers are comparing two stars that are known to have the same luminosity. Star A is observed to be 4 times brighter than s

tar B. How far away is Star A compared to Star B?

1 answer:

GaryK [48]3 years ago

7 0

The answer is two3988140

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Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon

posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

4 0

4 years ago

1. Is the collision between the ball and the pendulum elastic or inelastic? Justify your answer by calculating the kinetic energ

Nitella [24]

Answer:

So energy is not conserved and inelastic shock

Explanation:

In the collision between a bullet and a ballistic pendulum, characterized in that the bullet is embedded in the block, if the kinetic energy is conserved the shock is elastic and if it is not inelastic.

Let's find the kinetic energy just before the crash

K₀ = ½ m vₓ₀²

After the crash we can use the law of conservation of energy

Starting point. Right after the crash, before starting to climb

Em₀ = K = ½ (m + M) v₂²

Final point. At the maximum height of the pendulum

$Em_{f}$ = U = (m + M) g h

Where m is the mass of the bullet and M is the mass of the pendulum

Em₀ = Em_{f}

½ (m + M) v₂² = (m + M) g h

v₂ = √ 2g h

Now we can calculate the final kinetic energy

K_{f} = ½ (m + M) v₂²²

K_{f} = ½ (m + M) (2gh)

The relationship between these two kinetic energies is

K₀ / K_{f} = ½ m vₓ₀² / (½ (m + M) 2 g h)

K₀ / K_{f} = m / (m + M) vₓ₀² / 2 g h

We can see that in this relationship the Ko> Kf

So energy is not conserved and inelastic shock

5 0

4 years ago

The moon Phobos orbits Mars

shepuryov [24]

$27.9816 \times 10^{3} s$ is the period of orbit.

<u>Explanation: </u>

The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:

$\frac{T^{2}}{R^{3}}=\frac{4 \times \pi^{2}}{G \times M_{c e n t r a l}}$

Where,

T is the period of the orbit

R is the average radius of orbit

G is gravitational constant $6.673 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}$

Here, given data

$M=6.23 \times 10^{23} \mathrm{kg}$

$R=9.38 \times 10^{6} \mathrm{m}$

Substitute the given values, we get T as

$\frac{T^{2}}{\left(9.38 \times 10^{6}\right)^{3}}=\frac{4 \times(3.14)^{2}}{\left(6.673 \times 10^{-11}\right) \times 6.23 \times 10^{23}}$

$T^{2}=\frac{4 \times 9.8596 \times 825.29 \times 10^{18}}{41.57 \times 10^{12}}$

$T^{2}=\frac{32548.12 \times 10^{18-12}}{41.57}=782.97 \times 10^{6}$

Taking square root, we get

$T=27.9816 \times 10^{3} s$

4 0

3 years ago

A 0.9 kg metal bolt is heated to an unknown initial temperature. It is then dropped into a Calorimeter containing 0.15 kg of wat

Montano1993 [528]

Answer:

Whets nasılsın merhaba arkadaşlar ben bu etikete yazar nasılsın

8 0

3 years ago

What is the attractive or repulsive force between two ferromagnetic objects is called?

Zanzabum

I am not sure the answers is correct

Magnetic Field, Magnetic Field, 1) When two magnets are brought near each other, like poles repel; opposite poles attract. ... We like to represent this force effect of a magnet on iron-like objects with a concept called magnetic field

8 0

3 years ago

Read 2 more answers