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4 years ago

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Light passes through a single slit of width 8.32x10^-5 m. The first (m=1) diffraction minimum occurs at an angle of 0.347. What

is the wavelength of the light in nanometers?
(Hint: The answer will be between 400 and 700 nm.)

1 answer:

Diano4ka-milaya [45]4 years ago

6 0

Explanation:

theta = m wavelength/ silt width

gives angular position of minimas where m= 1,2,3...

As

0.347° = pi/180 × 0.347 rad = 0.006 rad

using above formula

0.006= 1 × wavelength/ 8.32 × 10^-5 m

wavelength = 0.006× 8.32 × 10^ -5 m

= 0.04992× 10^ -9 m

= 499× 10^ -9m

=499 nm

which is almost 500 nm

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