Answer:
Cohesion
Explanation:
Think of it like this. The water molecules STICK TOGETHER, so they COoperate.
COhesion COoperate
Answer:
0.95L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 1L
T1 (initial temperature) = 315K
P1 (initial pressure) = 1.10 atm
T2 (final temperature) = stp = 273K
P2 (final pressure) = stp = 1atm
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:
P1V1/T1 = P2V2/T2
1.1 x 1/315 = 1 x V2/273
Cross multiply to express in linear form.
315 x V2 = 1.1 x 273
Divide both side by 315
V2 = (1.1 x 273) /315
V2 = 0.95L
Therefore, the final volume of the system if STP conditions are established is 0.95L
It is given that the surface area of sphere is 4 π r² and its volume is (4/3 π r³)
With a diameter of 1.2 mm you have a radius of 0.6 mm so the surface area about 4.5 mm² and the volume is about 0.9 mm³
The total surface energy of the original droplet is (4.5 x 10⁻⁶ m x 72) = 3.24 x 10⁻⁴mJ
The five smaller droplets need to have the same volume as the original so:
5 V = 0.9 mm³ so the volume of smaller sphere will equal 0.18 mm³
Since this smaller volume still have volume (4/3 π r³) so r = 0.35 mm
Each of the smaller droplets has a surface are = 1.54 mm²
The surface energy of the 5 smaller droplet is then (5 x 1.54 x 10⁻⁶ m x 72) = 5.54 x 10⁻⁴ mJ
From this radius the surface energy of all smaller droplets is 5.54 x 10⁻⁴ and the difference in energy is (5.54 x 10⁻⁴) - (3.24 x 10⁻⁴) = 2.3 x 10⁻⁴ mJ
Therefore we need about 2.3 x 10⁻⁴ mJ of energy to change a spherical droplet of water of diameter 1.2 mm into 5 identical smaller droplets
