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viva [34]
3 years ago
7

How many grams are in 1 mole of Pb3(PO4)4?

Chemistry
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

Explanation:

Molar mass of Pb3(PO4)4 is 380+621.6 =1001.6 g/mole

 Molar comcentration = Reacting mass / Molar Mass

                       1 = Mr/1001.6

                       Mr = 1001.6g

kvasek [131]3 years ago
6 0

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2  .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 .  4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

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Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclobutane, C4H8
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Answer:

1. C4H8 + 6O2  -----> 4CO2 + 4H20

2. 3836.77 kcal

Explanation:

1. Balanced equation for the complete combustion of cyclobutane:

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2. Heat of combustion of cyclobutane = 650.3 kcal/mol

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