<h3>
Answer:</h3>
3.3 × 10²³ atoms Cu
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 0.54 moles Cu
[Solve] atoms Cu
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
3.25188 × 10²³ atoms Cu ≈ 3.3 × 10²³ atoms Cu
Answer:

Explanation:
We can use the formula for momentum to calculate the mass.

Answer:
neutrons are uncharged and electrons are negatively charged
Answer:
The volume of 0.80 grams of O2 is 0.56 L
Explanation:
Step 1 : Data given
Mass of O2 = 0.80 grams
Molar mass of O2 = 32 g/mol
STP = 1 mol, 1atm, 22.4 L
Step 2: Calculate moles of oxygen
Moles of O2 = Mass of O2 / molar mass of O2
Moles O2 = 0.80 grams / 32 g/mol
Moles O2 = 0.025 moles
Step 3: Calculate volume of O2
1 mol = 22.4 L of gas
0.025 moles = 0.025*22.4L = 0.56 L
The volume of 0.80 grams of O2 is 0.56 L
Lithium - Malleable, soft, and shiny
Lead - Opaque solid with higher density
Fluorine - Highly reactive gas
Krypton - Nonreactive gas
*<em>hope I helped :)</em>*