The final temperature :T₂=411.125 K = 138.125 °C
<h3>Further explanation</h3>
Given
T₁=-20 °C+273 = 253 K
V₁=40 ml
V₂=65 ml
Required
Final temperature
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
T₂=(V₂.T₁)/V₁
T₂=(65.253)/40
T₂=411.125 K = 138.125 °C
Charge ion for Mg is 2+
While 2+ is represents two electrons that had been released. It donors two electrons to oxide ions as oxide ions are 2-. 2- is represents as electron acceptor for two electrons. At the end, the empirical formula for this reaction is Mg2O2
I believe the answer to the first question is the golf ball because it requires less energy to move it so it will move faster than the bowling ball will with less energy. For the second question I could be wrong but I think the bowling ball has more kinetic energy because according to the equation KE= 0.5*m* x^{2} where KE represents the kinetic energy the m is the mass and x is the speed of the object the bowling ball will have more energy.
6 Li + N2 = 2 Li3N
6 moles Li ------------ 2 moles Li3N
0.24 moles Li ------- moles Li3N
moles Li3N = 0.24 *2 / 6
moles Li3N = 0.48 / 6 => 0.08 moles
Answer B
You should use Avogadro’s number for the conversion, because Avogadro’s Law states that there are 6.02 x 10^23 atoms per 1 mol of that substance.
