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stich3 [128]
3 years ago
15

А 2. Find the values of x and 3x.

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

For the equation y = x - 3x + 4x + 5, tind the point of inflection. ...  Find the indicated derivative using the definition f(x) = 2x4+3x3-2x+7: f'(0).

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I need these answers as ap
azamat
I did out all my work but it got deleted. Hope you don't mind just answers.
5) 10
6) 32
7) 64 pi
8) A=64 pi C=16 pi
9) A=110.25 pi C=21 pi
10) A=1024/pi C=64
11) L=4sqrt(5) or about 9 midpoint is (1,4)
12) L=sqrt(37) or about 6 midpoint is (-1,-3.5)
Sorry I couldn't show work, hope this helps :)
6 0
3 years ago
write an equation in point-slope form of the line that passes through the (7,-4) and has a slip of m=-6?
Leokris [45]

Answer:

y+4=-6(x-7)

Step-by-step explanation:

Point slope form is giving by the equation

y - y = m (x - x)

M being the slope and y and x being points

All you have to do is plug in your slope and point:

(y + 4) = -6 (x - 7)

8 0
3 years ago
Please help, i need this done asap!
Bond [772]

Answer:

}\frac{\sqrt{2} }{2} or 0.707

Step-by-step explanation:

cos(315) is equivalent to cos (\frac{7\pi }{4})

You can look at the unit circle to find the cos value for this. Keep in mind that cos is the x value of the corresponding coordinate.

7 0
3 years ago
What is the answer negative one times the sum of one and seven times a number, decreased by 6 times the difference of negative s
Setler79 [48]

Answer:

The number is -79.

Step-by-step explanation:

Let's set up equation for the given information.

Let the number as 'x'

Negative 1 times the sum of one and seven times a number x could be written as -1(1+7 x).

Now, 6 times the difference of negative seven and a number could be written as

6(-7-x)

Now,

-1(1+7 x) decreased by 6(-7-x) equals 36

So, we can set up equation as

-1(1+7 x)-6(-7-x)=36

Solve the equation for x

-1-7 x-42+6 x=36

Combine like terms

-x-43 =36

Add both sides 43

-x=79

Divide both sides by -1.

x=79

5 0
3 years ago
X^2-5x=-4 . I need to find the zeroes
GrogVix [38]
The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:

X² - 5x + 4 = 0

Factor the equation:

(x - 1)(x - 4) = 0

Now calculate each piece separately, starting with the first one:

x - 1 = 0

Add 1 to both sides of the equation:

x = 1

We have proven that x = 1. Now calculate the second piece:

x - 4 = 0

Add 4 to both sides of the equation:

x = 4

We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.

I hope this helps!
4 0
4 years ago
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