Question

PLZ HELP WITH ME WITH MY MATH HOMEWORK!!!!! SHOW WORK!!!!!

Answer 1

Explanation:

(I). 5/6 (4X+8) = (3/8) X - (1/4)

→ [{5(4X) + 5(8)}/6] = (3/8)X - (1/4)

→ [{20X + 40}/6] = (3/8)X - (1/4)

→ [{(20X/6) + (40/6) = (3/7)X - (1/4)

Now,

shift all variables fraction on LHS and constant fraction on RHS.

→ [(20X/6) - (3X/7)]= -(1/4) - (40/6)

Take the LCM of LHS denominator of 6&7 is 42.

→ [(140X - 18X)/42] = -(1/4)-(40/6)

→ [(122X)/42] = -(1/4)-(40/6)

Again take the LCM of the denominator in RHS i.e 4&6 is 12.

→ [(122X)/42] = (-12 - 80)/4

→ [(122X)/42] = (-92)/4

By doing Cross multiply the fraction, we get

→ 4(122X) = 42(-92)

→ 488X = -3 864

→ X = -3 864÷488

Therefore, X = -3864/488

Answer: Hence, the value of X for the given problem is -3864:488.

Explanation:

ii)Given algebraic equation is: 5(3p-5)+4p=5p-6(p+4)

→ 15p - 25 + 4p = 5p - 6p + 24

Shift all variables in LHS and constant on RHS.

→ 15p + 4p +6p = 25+24

→ 19p + 6p = 49

→ 25p = 49

Shift the number 25 from LHS to RHS.

Therefore, p = 49/25.

Answer: Hence, the value of P for the given algebraic equation is 49/25.