The correct answer to the statement " Do two bodies have to be in physical contact to exert a force upon one another " is:
No, the gravitational force is a field force and does not require physical contact to exert
a force.
The correct option is a.
<h3>Why two bodies do not have to be in physical contact to exert a force upon one another as a result of gravitational force.</h3>
It has been practically proven that two bodies can exert a force upon each other even if there is no physical contact between them. This can as a result of gravity.
That being said, a magnetic attraction can also exert a force between two different bodies upon one another.
So therefore, it can be deduced from above that two different bodies do not have to be in physical contact before they exert a force upon one another.
Read more on force:
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Steps:
1)Data:
q1=charge of first balloon=1.2 × 10^-6
q2=charge of second balloon=1.2 × 10^-6
Condition:q1=q2
then for convenience,we say q instead of q1 and q2.
Radius=r=5*10^-1
Radius is the distance between balloons!
Magnitude of repulsive force=F=?
2)Solution:
F=kq1q2/r^2
As q1=q2=q
So
F=kqq/r^2
=kq^2/r^2
Putting values:
F=((9*10^9)(1.2 × 10^-6)^2)/(5*10^-1)^2
Using calculator:
F=0.05184 N
Answer:
N/kg
Explanation:
newton/kilogram is the answer.please mark me brainliest
Answer:
Vf= 7.29 m/s
Explanation:
Two force act on the object:
1) Gravity
2) Air resistance
Upward motion:
Initial velocity = Vi= 10 m/s
Final velocity = Vf= 0 m/s
Gravity acting downward = g = -9.8 m/s²
Air resistance acting downward = a₁ = - 3 m/s²
Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²
( Acceleration is consider negative if it is in opposite direction of velocity )
Now
2as = Vf² - Vi²
⇒ 2 * (-12.8) *s = 0 - 10²
⇒-25.6 *s = -100
⇒ s = 100/ 25.6
⇒ s = 3.9 m
Downward motion:
Vi= 0 m/s
s = 3.9 m
Gravity acting downward = g = 9.8 m/s²
Air resistance acting upward = a₁ = - 3 m/s²
Net acceleration = a = g - a₁ = 9.8 - 3 = 6.8 m/s²
Now
2as = Vf² - Vi²
⇒ 2 * 6.8 * 3.9 = Vf² - 0
⇒ Vf² = 53. 125
⇒ Vf= 7.29 m/s
Answer:
Few millimeter thick aluminium, water, wood, acrylic glass or plastic.
Explanation:
The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.
These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.
