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2 years ago

I need help with air resistance...

1 answer:

3 0

Mar 4, 2004 #1 FabioTTT the formula: R = (.5)DpAv^2 is used to determine how much air resistance (resistive force) is being placed on the object. R is the Resistive force. D is some dimensionless empirical quantity called the drag coefficient p is the density of air A is the cross-sectional area of the object (surface area) v is velocity My question is, is the density of air some constant that should be already given to me? also, how would i go about finding the drag coefficient? I'm asking this because in physics we're doing a lab in wich we drop a cofee filter... and we record its time to reach a certain height (which im guessing is to be able to calulate for the terminal velocity). So in other words, I have all of these variables except for R, D, and p. Can anyone help me out? Phys.org - latest science and technology news stories on Phys.org

Reference https://www.physicsforums.com/threads/need-help-with-air-resistance.15678/

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avanturin [10]

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Answer: Option D

Explanation:

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

$potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)$

Where,

m – mass of object

Acceleration due to gravity = $9.8 \mathrm{m} / \mathrm{s}^{2}$

h = 500 meters

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As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

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Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

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2 years ago

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Answer:

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Explanation:

We know that pressure, P = ρgh where ρ = density of material, g = 9.8 m/s and h = height.

Since density of liquid = 2 × density of water = 2 × 1000 kg/m = 2000 kg/m³

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For the same pressure, the height for water is h = P/ρg = 101500/(1000 × 9.8) = 10.36 m

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ρ₁h₁ = ρ₂h₂

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