All categories

4 years ago

I need help with air resistance...

1 answer:

3 0

Mar 4, 2004 #1 FabioTTT the formula: R = (.5)DpAv^2 is used to determine how much air resistance (resistive force) is being placed on the object. R is the Resistive force. D is some dimensionless empirical quantity called the drag coefficient p is the density of air A is the cross-sectional area of the object (surface area) v is velocity My question is, is the density of air some constant that should be already given to me? also, how would i go about finding the drag coefficient? I'm asking this because in physics we're doing a lab in wich we drop a cofee filter... and we record its time to reach a certain height (which im guessing is to be able to calulate for the terminal velocity). So in other words, I have all of these variables except for R, D, and p. Can anyone help me out? Phys.org - latest science and technology news stories on Phys.org

Reference https://www.physicsforums.com/threads/need-help-with-air-resistance.15678/

You might be interested in

*Urgent* I WILL GIVE BRAINLIEST

Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0

3 years ago

A satellite that is in a circular orbit 230 km above the surface of the planet Zeeman-474 has an orbital period of 89 min. The r

ehidna [41]

Answer:

Mass of the planet = 6.0 × $10^{24}$

Explanation:

Time period = 2π (R + h) / v

Orbital speed (v) = √GM / (R + h)

T² = 4π² (R + h)² / (GM/ (R + h))

= 4π² (R + h)³ / GM

making m the subject of the formula

m = 4π² (R + h)³ / GT²

= 4π² ( 6.38 × $10^{6}$ + 230 × 10³ )³ / ( 6.67 × $10^{-11}$ ) × (89 × 60)²

= 4π² ( 6610000)³ / ( 6.67 × $10^{-11}$ ) × (89 × 60)²

= 5.99 × $10^{24}$

= 6.0 × $10^{24}$

5 0

3 years ago

In a circuit of 2 lamps in parallel if the current in one lamp is 2a the current in the other lamp is?

ioda

In a circuit having 2 lamps are connected in parallel to a battery

then the two lamps will be having the same potential as the battery

i.e

$V_{1} = V_{2} = V_{battery}$

As per Ohm's law,

$I_{1} = \frac{V_{1}}{R_{1}}$ and $I_{2} = \frac{V}{R_{2} }$

In other words, each lamp's current is inversely related to its individual resistance. We only know the current in one of the bulbs in this specific instance. We would therefore need further information in order to calculate the current in the other light. Therefore, there isn't enough data to make a statement.

Under the assumption that all physical parameters, including temperature, remain constant, Ohm's law asserts that "the voltage across a conductor is directly proportional to the current flowing through it".

Learn more about Ohm's law here

brainly.com/question/2264542

#SPJ4

4 0

2 years ago

Why is digital forensics important?

netineya [11]

Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.

4 0

2 years ago

EEG Voltage is: Select one: a. Flow of electrons through a pathway and the unit is the Ampere b. A measure of the opposition to

zaharov [31]

Answer:

The answer is d. The potential charge difference between two points and the unit is the Volt

Explanation:

The voltage is the difference in electric charge between two points that pushes electrons along the circuit from the highest charged (positive) pole to the lowest charged (negative) .

5 0

3 years ago