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sertanlavr [38]
3 years ago
15

I need help with air resistance...

Physics
1 answer:
Ugo [173]3 years ago
3 0
Mar 4, 2004 #1 FabioTTT the formula: R = (.5)DpAv^2 is used to determine how much air resistance (resistive force) is being placed on the object. R is the Resistive force. D is some dimensionless empirical quantity called the drag coefficient p is the density of air A is the cross-sectional area of the object (surface area) v is velocity My question is, is the density of air some constant that should be already given to me? also, how would i go about finding the drag coefficient? I'm asking this because in physics we're doing a lab in wich we drop a cofee filter... and we record its time to reach a certain height (which im guessing is to be able to calulate for the terminal velocity). So in other words, I have all of these variables except for R, D, and p. Can anyone help me out? Phys.org - latest science and technology news stories on Phys.org

Reference https://www.physicsforums.com/threads/need-help-with-air-resistance.15678/
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The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>

Explanation:

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3 0
3 years ago
A 125kg bumper car going 18.5 m/a bumps a 187.kkg bumper car at rest. if the first car (125kg) bounces back at 8 m/s what is the
kozerog [31]
  <span><span>Imagine we have a 2 lb ball of putty moving with a speed of 5 mph striking and sticking to a 18 lb bowling ball at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v1. To find v1, use momentum conservation: 2x5=(18+2)v1, v1=0.5 mph. </span><span>Next, imagine we have a 18 lb bowling ball moving with a speed of 5 mph striking and sticking to a 2 lb ball of putty at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v2. To find v2, use momentum conservation: 18x5=(18+2)v2, v2=4.5 mph. </span><span>
</span><span>
</span><span>now figure out your problem its really easy let me know if you need more help  </span></span>
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Machines A, B, and C do the same amount of work, but they each take a different amount of time. Machine A takes more time as com
Amiraneli [1.4K]
So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C. 
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A mercury thermometer is used to measure the temperature of boiling water but why do you think the mountainous travel to cold re
melamori03 [73]

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7 0
2 years ago
Sledding down a hill, you are traveling at 10 m/s when you reach the bottom. You (inertia 80 kg ) then move across horizontal sn
RSB [31]

Answer:

V = 0.32 m /s

Explanation:

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= (80+8) x 10 = 880 kg. m/s When the man jumps off the sledge , the velocity of the sledge will remain intact at 10 m/s

When the sledge hits the boulder and bounces back the momentum of the sledge - boulder system will remain conserved .

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Change in the momentum of boulder

= 400 V -0

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400V = 128

V = 0.32 m /s

5 0
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