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CaHeK987 [17]
3 years ago
7

a fan acquires a speed of 180 rpm in 4s, starting from rest. calculate the speed of the fan at the end of the 5th second startin

g from rest. Assume angular acceleration to be uniform
Physics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

225 rpm

Explanation:

The angular acceleration of the fan is given by:

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

where

\omega_f is the final angular speed

\omega_i is the initial angular speed

\Delta t is the time interval

For the fan in this problem,

\omega_i = 0\\\omega_f = 180 rpm\\\Delta t=4 s

Substituting,

\alpha = \frac{180-0}{4}=45 rpm/s

Now we can find the angular speed of the fan at the end of the 5th second, so after t = 5 s. It is given by:

\omega' = \omega_i + \alpha t

where

\omega_i = 0\\\alpha = 45 rpm/s\\t = 5 s

Substituting,

\omega' = 0 + (45)(5)=225 rpm

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Answer:

6.85 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum.

In fact, since there are no external forces acting, the total momentum before and after must be conserved. So we can write:

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m_1 = 9.13\cdot 10^3 kg is the initial mass of the car

v_1 = 3.15 m/s is the initial speed of the car

m_2 = 9.13\cdot 10^3 kg - 4.20\cdot 10^3 kg=4.93\cdot 10^3 kg is the mass of the car after the load of gravel is dropped

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Solving for v2, we find

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3 years ago
When a wave is acted upon by an external damping force what happens to the energy of the wave
Nimfa-mama [501]

Answer:

A-the energy of the wave decreases gradually

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when a wave is acted upon by an external damping force the energy of the wave decreases gradually.

The energy degrades into the form of heat which is considered to be of less value and use. The reason is because it disperses and spreads more widely.

So therefore it end up as heat with a little sound but that is close to none because that too disperses into heat i.e. decreased form of energy.

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g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
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To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

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da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

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Where,

m = mass

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From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

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dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

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But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d
Georgia [21]

Answer:

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The change in entropy, ∆S = ∆H/T

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For,

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III. A system at equilibrium, ∆S = 0.

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