Answer:
Hey there!
5(v+3)-10v>-10
5v+15-10v>-10
-5v+15>-10
-5v>-25
v<5
Let me know if this helps :)
Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is
and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

where c is the number of server (in this case, one server).
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Step-by-step explanation:
just draw a square that's big enough to fit all wanted plots (10 by 10 is recommended)
There’s no picture so I can’t help you sorry :(