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2 years ago

PLEASE HELP ITS IXL

Mathematics

1 answer:

Harrizon [31]2 years ago

4 0

Probally neither since she made both of the scents not smell citrusy, she would have to put the same amout of water in both, and she had to doublr it for the bucket... well since itd a bucket. But its probally still neither.

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A group of four components is known to contain two defectives. An inspector tests the components one at a time until the two def

Stells [14]

Answer:

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

Step-by-step explanation:

Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6

Y can only take values of 2, 3 and 4

So, Probability of Y = P(Y) = 1C(Y-1) / 6

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

4 0

3 years ago

The sum of two consecutive integers is -207

Maru [420]

Answer:

They would be -104 and -103.

Step-by-step explanation:

-103 + (-104)

= -103 - 104

= -207.

3 0

3 years ago

What's the smallest possible perimeter of a rectangle with an area of 35 cm? (36 small squares 1 cm by 1 cm)

vfiekz [6]

Answer:

12 miles per hour...........

6 0

2 years ago

Helppo please<br> PLSS<br><br> PLSS

soldi70 [24.7K]

Answer:m1=-3,m2=3 the equation has 2 solutions

7 0

3 years ago

You want to create a 99% confidence interval with a margin of error of .5. Assuming the population standard deviation is equal t

miss Akunina [59]

Answer:

Sample size minimum is 60

Step-by-step explanation:

given that you want to create a 99% confidence interval with a margin of error of .5.

The population standard deviation is equal to 1.5

i.e. $\sigma = 0.5$

Confidence level = 99%

Since population std deviation is known, we can use Z critical value for finding margin of error

Z critical value for 99% = 2.58

Margin of error = $2.58*\frac{1.5}{\sqrt{n} }$

Equate this to 0.5 and solve for n

$2.58*\frac{1.5}{\sqrt{n} }=0.5\\\sqrt{n} =7.74\\n =59.90\\n=60$

8 0

3 years ago

PLEASE HELP ITS IXL ​

PLEASE HELP ITS IXL