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NISA [10]
2 years ago
15

PLEASE HELP ITS IXL ​

Mathematics
1 answer:
Harrizon [31]2 years ago
4 0
Probally neither since she made both of the scents not smell citrusy, she would have to put the same amout of water in both, and she had to doublr it for the bucket... well since itd a bucket. But its probally still neither.
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Please help meee!!!!!
Mila [183]
-4/1 because y is going down by four and x is going down by 1.
4 0
3 years ago
Read 2 more answers
The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.
Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

\overline{CD} = 12 \: units

\overline{C'D'}

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

\overline{C'D'} = n \times \overline{CD}

Option A

If n=3/2, then

\overline{C'D'}  =  \frac{3}{2}  \times 12 = 3 \times 6 = 18 \: units

This is true.

Option B

If n=4, then

\overline{C'D'} = 4 \times 12 = 36 \: units

This is false.

Option C

If n=8, then

\overline{C'D'} = 8 \times 12 = 96 \: units

This too is false.

Option D

If n=2, then

\overline{C'D'} = 2 \times 12 = 24 \: units

This is true

Option E

If n=3/4, then

\overline{C'D'} =  \frac{3}{4}  \times  12

\overline{C'D'} =  3 \times 3 = 9 \: units

This is also true.

4 0
3 years ago
A newspaper publisher wants to check its daily output of about 300,000 newspapers to be sure each includes a comics section. Exp
stiv31 [10]

Number of Newspaper Published in a day = 300,000

Each news paper must include a Comic section. To check whether each newspaper has comic section or not, the publisher must make a sample Size of 500 or 1,000 will be good . That is , the publisher has to check between Sample size of  either 600 or 300 newspapers ,whether it contain a comic section or not.

So, Just Taking  a newspaper from a  sample size of 600 or 1500 newspapers or 500 or 1000 newspaper and then checking whether it contains Comic section or not will be best way that publisher can adopt.

Time must be kept in mind by the publisher while choosing the sample size.

3 0
3 years ago
Read 2 more answers
The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 5 years.
Oksana_A [137]

Complete question is in comment section :

Answer:

68%

Step-by-step explanation:

Mean = 25

Standard deviation = 5

The percentage of trees between 20 and 30

20 trees = 1 standard deviation below the mean ; mean - 1(standard deviation)

25 - 5 = 20

30 trees = 1 standard deviation above the mean ;

Mean + 1(standard deviation) ;

25 + 5 = 30

This means, 20 and 30 lies ±1 standard deviation from the mean which according to the empirical rule is 68%

According to the empirical rule :

7 0
3 years ago
Will ran the diagonal distance across a square field measuring 40 yards on each side. James Ran the diagonal distance across A r
ozzi

Answer:

<u>Will</u> ran the longer distance.

He run <u>56.40 yards</u> longer distance.

Step-by-step explanation:

<u><em>The question is incorrect so the correct question is below.</em></u>

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the distance across a rectangular field with a length of 25 yards and a width of 35 yards. Who ran a longer distance,and how much longer did he run?

Now, to find the person who ran longer distance and the distance he run.

Will ran the diagonal distance across a square field.

The length of square field = 40 yards.

So, we put formula to get the diagonal of square:

Diagonal=length\sqrt{2}

Diagonal=40\times \sqrt{2}

Diagonal=40\times 1.41

Diagonal=56.40\ yards.

Thus, Will ran 56.40 yards diagonal distance of the square field.

Now, James ran the distance across a rectangular field with a length of 25 yards and a width of 35 yards.

So, to get the diagonal of rectangular field we use pythagorean theorem:

Diagonal^2=length^2+width^2

Diagonal^2=25^2+35^2

Diagonal^2=625+1225

Diagonal^2=1850

<em>Using square root on both sides we get:</em>

Diagonal=43.01\ yards.

Hence, James ran the diagonal distance 43.01 yards across the rectangular field.

<em>Now, we see the diagonal distance of both Will and James.</em>

<em>As, Will ran 56.40 yards and James ran 43.01 yards.</em>

<em>So, Will ran longer distance than James. And he run 56.40 yards</em>.

Therefore, Will ran the longer distance.

He run 56.40 yards longer distance.

4 0
4 years ago
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